Balance the following oxidation-reduction reaction as if it were to occur in a basic solution. I(aq) + ClO-(aq) → I3¯(aq) + Cl-(aq) HOW DO WE GET THERE? For the reduction half-reaction, which half-reaction correctly balances the elements on both sides? ClO (aq) + H2O(1) → Cl-(aq) + 2 H+(aq) ClO-(aq) → CI-(aq) 2 H*(aq) + ClO-(aq) → Cl¯(aq) + H20(1) Clo-(aq) → Cl-(aq) + H20(1) Clo (aq) – CI-(aq) + H20(1) + 2 H*(aq)
Balance the following oxidation-reduction reaction as if it were to occur in a basic solution. I(aq) + ClO-(aq) → I3¯(aq) + Cl-(aq) HOW DO WE GET THERE? For the reduction half-reaction, which half-reaction correctly balances the elements on both sides? ClO (aq) + H2O(1) → Cl-(aq) + 2 H+(aq) ClO-(aq) → CI-(aq) 2 H*(aq) + ClO-(aq) → Cl¯(aq) + H20(1) Clo-(aq) → Cl-(aq) + H20(1) Clo (aq) – CI-(aq) + H20(1) + 2 H*(aq)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Balance the following oxidation-reduction reaction as if it were to occur in a basic solution.
I(aq) + ClO (aq) → I3 (aq) + Cl-(aq)
HOW DO WE GET THERE?
For the reduction half-reaction, which half-reaction correctly balances the elements on both sides?
clO (aq) + H20(1) → CI-(aq) + 2 H*(aq)
ClO-(aq) → CI-(aq)
2 H+(aq) + ClO-(aq) → Cl-(aq) + H20(I)
clo-(aq) → Cl-(aq) + H20(I)
clO (aq) → Cl-(aq) + H20(I) + 2 H*(aq)
Check
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Transcribed Image Text:Balance the following oxidation-reduction reaction as if it were to occur in a basic solution.
I(aq) + ClO (aq) → I3 (aq) + Cl-(aq)
HOW DO WE GET THERE?
For the reduction half-reaction, which half-reaction correctly balances the elements on both sides?
clO (aq) + H20(1) → CI-(aq) + 2 H*(aq)
ClO-(aq) → CI-(aq)
2 H+(aq) + ClO-(aq) → Cl-(aq) + H20(I)
clo-(aq) → Cl-(aq) + H20(I)
clO (aq) → Cl-(aq) + H20(I) + 2 H*(aq)
Check
Next (4 of 8)
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