Baking soda (NaHCO3) decomposes on heating as follows: 2 NaHCO3(s) -> Na2CO3(s) + CO2(g) + H2O(1I) AHrxn = -127.4 kJ Calculate the standard enthalpy of formation of NaHCO3(s) in units of kJ/mol using the following information: AH¡(CO2(g)] = -374 kJ AH¡[N22CO3(s)] = -1,135 kJ AH:{H20(1)] = -289 kJ. IMPORTANT: Enter both the sign and the value (no units) with O decimal places (a whole number). Type your answer.

Baking soda (NaHCO3) decomposes on heating as follows: 2 NaHCO3(s) -> Na2CO3(s) + CO2(g) + H2O(1I) AHrxn = -127.4 kJ Calculate the standard enthalpy of formation of NaHCO3(s) in units of kJ/mol using the following information: AH¡(CO2(g)] = -374 kJ AH¡[N22CO3(s)] = -1,135 kJ AH:{H20(1)] = -289 kJ. IMPORTANT: Enter both the sign and the value (no units) with O decimal places (a whole number). Type your answer.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

The standard state of carbon is graphite. ΔH°f,diamond is +1.896 kJ/mol. Diamonds are normally weighed in units of carats, where 1 carat = 0.200 g Determine the standard enthalpy of the reaction for the conversion of a 3.61 -carat diamond into an equivalent mass of graphite.
With a platinum catalyst, ammonia will burn in oxygen to give nitric oxide, NO. 4NH3 (9) + 502 (g) → 4NO(9) + 6H20(g) AH = -906 kJ What is the enthalpy change for the following reaction? NO(9) + H2O(9) → NH3 (9) + O2(g) Enthalpy change : kJ
A chemist measures the enthalpy change AH during the following reaction: Fe(s) + 2 HCl(g) →FeCl₂(s) + H₂(g) Use this information to complete the table below. Round each of your answers to the nearest kJ/mol. reaction AH=157. kJ FeCl₂ (s) + H₂(g) → Fe(s) + 2HC1 (g) 2Fe (s) + 4H C1 (g) 3 FeCl₂ (s) + 3H₂(g) 2FeCl₂ (s) + 2H₂(g) 3Fe (s) + 6HCl (g) ΔΗ [ kJ kJ kJ 0x x10 × Ś
When 6.54 grams of Zn is placed in 500.0 mL of 1.00 M CuSO4(aq) in a coffee cup calorimeter, it reacts completely to displace copper. The temperature of the solution rises from 20.0˚C to 30.4˚C. Assume the coffee cup itself gains no heat and that the solution has the same density (1.00 g/mL) and specific heat (4.184 J/g˚C) as pure water. (a) How much heat does the solution gain during this reaction? (in J)
2. Slaked lime (Ca(OH)2(s)) is produced when lime (calcium oxide, Cao (s)) reacts with liquid water. 65.2 kJ of heat is released for each mol of Ca(OH)2 that is produced. (a) Write a thermochemical equation for the reaction. (b) What is the enthalpy change when 523.3 kg of lime reacts with excess water?
A scientist measures the standard enthalpy change for this reaction to be -739.4 kJ/mol:2CO(g) + 2 NO(g)2CO2(g) + N2(g)Based on this value and the standard formation enthalpies for the other substances, the standard formation enthalpy of CO(g) is
Calculate enthalpy of reaction given reaction enthalpies for proposed steps in a process. K+(g) + Cl-(g) → KCI(s) KCI (LE) = ? Cl2(g) → 2CI(g) Cl-CI (BE) = 243 kJ/mol K(g) → K+(g) + 1e- K (IE) = 419 kJ/mol K(s) → K(g) K (AHsub) = 89.0 kJ/mol Cl(g) + 1e- → CI-(g) CI (EA) = -349 kJ/mol K(s) + 1/2C12(g) > KCI(s) KCI (AH;) = -436.5 kJ/mol
Please don't provide handwritten solution ...
Given the standard enthalpy changes for the following two reactions: (1) 2Pb(s) + O₂(g) → 2PbO(s) (2) 2Zn(s) + O₂(g) → 2ZnO(s) Standard enthalpy change = AH-434.6 kJ AH° -696.6 kJ What is the standard enthalpy change for the following reaction? (3) PbO(s) + Zn(s) → Pb(s) + ZnO(s) AH° = ? KJ =