Bag # 2 3 5 Contents Write Chemical Formula Calculate Molar Mass (g/mol) Manganese (IV) oxide MnO₂ 86.94g/mol Sulfur Copper Sodium Bicarbonate Carbon Mass (g) 12.08 g 12.10 g 16.8 g # of moles 12.08g(1 mol/86.94g) =0.1390 mol 1.70 mol # of particles (atoms/molecules/ions/formula units as indicated) # oxide ions 0.138946mol(6.022 x 10²0 formula units/1 mol)(2 oxide ions/formula unit) = 1.673 x 10¹ oxide ions # atoms (total) # atoms # sodium atoms #atoms
Bag # 2 3 5 Contents Write Chemical Formula Calculate Molar Mass (g/mol) Manganese (IV) oxide MnO₂ 86.94g/mol Sulfur Copper Sodium Bicarbonate Carbon Mass (g) 12.08 g 12.10 g 16.8 g # of moles 12.08g(1 mol/86.94g) =0.1390 mol 1.70 mol # of particles (atoms/molecules/ions/formula units as indicated) # oxide ions 0.138946mol(6.022 x 10²0 formula units/1 mol)(2 oxide ions/formula unit) = 1.673 x 10¹ oxide ions # atoms (total) # atoms # sodium atoms #atoms
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question

Transcribed Image Text:Moles, Mass and Number of Particles Activity
Part A: Complete the chart by calculating the missing information.
Use your orange Periodic Table and round significant figures accordingly.
Pro tip! If you are using a calculated value in a subsequent calculation, keep at least an extra 2
significant figures in your calculation, and round your final answer.
Contents
Bag #
Write Chemical Formula
Calculate Molar Mass
Mass (g)
# of moles
(g/mol)
Manganese (IV) oxide
1
MnO₂
86.94g/mol
12.08g(1 mol/86.94g)
=0.1390 mol
Sulfur
2
Copper
3
1.70 mol
Sodium Bicarbonate
Carbon
1.89 mol
Zinc
Sodium Chloride
Barium Chloride
0.264 mol
Lactose
S
4
5
6
7
8
9
12.08 g
12.10 g
16.8 g
39.49 g
3.400 g
110.8 g
# of particles
(atoms/molecules/ions/formula units as indicated)
# oxide ions
0.138946mol(6.022 x 10²¹ formula
units/1 mol)(2 oxide ions/formula unit)
= 1.673 x 10¹ oxide ions.
# atoms (total)
#atoms
# sodium atoms
#atoms
#atoms (total)
#formula units
#chloride ions
#atoms (total)
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