BacO3+Ba2++C032 reaction was givenCarbonate anion[HCO3][OH¯][Coz?]CO3?-+H20O+HCO3-+OHKb1=andHCO3 +H2O+H2CO3+OH¯[H?c03][OH¯][HCO5]Kb2=It is known that thereis hydrolysis in the form. Since Ka1 = 1.45 x 10-7, Ka2 = 4.7 x 10-11 andKcBaco3 = 5.1 x 10°, calculate the solubility of the BaCO3 salt at pH = 8ww mmw n w mnand 12 depending on the pH value.wwww h m w

The solubility product constant or the equilibrium constant is a measure of the extent to which the…

Baco3+Ba2++CO3² reaction was given Carbonate anion Co3?-+H2O+HCO3-+OH [HCO3][OH¯] [Co3?] Kb1= and HCO3 +H2O+H2CO3+OH¯ [H?c03][OH¯] [HCO]] It is known that there Kb2= is hydrolysis in the form. Since Ka1 = 1.45 x 107, Ka2 = 4.7 × 10-11 and KCBaco3 = 5.1 x 10°, calculate the solubility of the BaCO3 salt at pH = 8 wwwm %3! and 12 depending on the pH value. ww m

Baco3+Ba2++CO3² reaction was given Carbonate anion Co3?-+H2O+HCO3-+OH [HCO3][OH¯] [Co3?] Kb1= and HCO3 +H2O+H2CO3+OH¯ [H?c03][OH¯] [HCO]] It is known that there Kb2= is hydrolysis in the form. Since Ka1 = 1.45 x 107, Ka2 = 4.7 × 10-11 and KCBaco3 = 5.1 x 10°, calculate the solubility of the BaCO3 salt at pH = 8 wwwm %3! and 12 depending on the pH value. ww m

Chemistry

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Question

BacO3+Ba2++C032 reaction was given
Carbonate anion
[HCO3][OH¯]
[Coz?]
CO3?-+H20O+HCO3-+OH
Kb1=
and
HCO3 +H2O+H2CO3+OH¯
[H?c03][OH¯]
[HCO5]
Kb2=
It is known that there
is hydrolysis in the form. Since Ka1 = 1.45 x 10-7, Ka2 = 4.7 x 10-11 and
KcBaco3 = 5.1 x 10°, calculate the solubility of the BaCO3 salt at pH = 8
ww m
mw n w mn
and 12 depending on the pH value.
wwww h m w

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