BaCl₂ H₂O(s) loses water when it is heated in an oven: BaCl₂ H₂O(s) BaCl₂ (s) + H₂O(g) PH₂0 AH° = 63.11 kJ/mol at 25 °C Write the equilibrium constant for this reaction. Find the vapor pressure of H₂O (PH₂0) above BaCl₂ · H₂O(s) at 298 K. AS° = +148 J/(K · mol) at 25 °C T = If AHⓇ and A.Sº are not temperature dependent (a poor assumption), estimate the temperature at which PH₂0 above BaCl₂ H₂O(s) will be 1 bar. bar °C

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BaCl₂ H₂O(s) loses water when it is heated in an oven:
PH₂O
.
BaCl₂ · H₂O(s) ⇒ BaCl₂ (s) + H₂O(g)
T =
AH° = 63.11 kJ/mol at 25 °C
.
Write the equilibrium constant for this reaction. Find the vapor pressure of H₂O (PH₂0) above BaCl₂ · H₂O(s) at 298 K.
AS°= +148 J/(K mol) at 25 °C
If AH° and A.Sº are not temperature dependent (a poor assumption), estimate the temperature at which PH₂0 above
BaCl₂ H₂O(s) will be 1 bar.
bar
°C
Transcribed Image Text:BaCl₂ H₂O(s) loses water when it is heated in an oven: PH₂O . BaCl₂ · H₂O(s) ⇒ BaCl₂ (s) + H₂O(g) T = AH° = 63.11 kJ/mol at 25 °C . Write the equilibrium constant for this reaction. Find the vapor pressure of H₂O (PH₂0) above BaCl₂ · H₂O(s) at 298 K. AS°= +148 J/(K mol) at 25 °C If AH° and A.Sº are not temperature dependent (a poor assumption), estimate the temperature at which PH₂0 above BaCl₂ H₂O(s) will be 1 bar. bar °C
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