Background: A small circular loop of wire of radius 5 cm and resistance 1E-3 Ω is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.) (G) Based on Lenz’s law, what is the direction of the induced electric field in the wire of the small loop:______ (H) magnitude of the average current I in the wire of the small loop:______A
Background: A small circular loop of wire of radius 5 cm and resistance 1E-3 Ω is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.) (G) Based on Lenz’s law, what is the direction of the induced electric field in the wire of the small loop:______ (H) magnitude of the average current I in the wire of the small loop:______A
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter15: Fluid Mechanics
Section: Chapter Questions
Problem 3P
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Background:
A small circular loop of wire of radius 5 cm and resistance 1E-3 Ω is centered inside a large circular loop of wire of radius 50 cm. The larger loop, which initially carries a current of 8 A, is cut and its current is reduced to zero over a time interval of 1E-6 s. Our goal will be to find the average current in the smaller loop during this time interval. (The magnetic field of the larger loop is approximately constant over the smaller loop.)
(G) Based on Lenz’s law, what is the direction of the induced electric field in the wire of the small loop:______
(H) magnitude of the average current I in the wire of the small loop:______A
![50 сm
10 сm
8.0 A
R = 1.0 × 10-3 Q](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1fd59d57-6681-48f5-9b95-ca8cd0e1f3f1%2Fa84c37e1-6d8c-407c-811b-6ec7064a1f17%2Fefzm5s_processed.png&w=3840&q=75)
Transcribed Image Text:50 сm
10 сm
8.0 A
R = 1.0 × 10-3 Q
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