B3: a) Differentiate from first principles the function f(x) = x² + 2x – 1. b) A particle is moving in a straight line such that at time t (sec) its acceleration is given by a(t) = 2t – 1 m/s². Derive a general expression for v(t), the velocity at time t, and the specific solution for v(0) = -1 m/s. c) [5] Evaluate (3x2 — х + 2) dx -1
B3: a) Differentiate from first principles the function f(x) = x² + 2x – 1. b) A particle is moving in a straight line such that at time t (sec) its acceleration is given by a(t) = 2t – 1 m/s². Derive a general expression for v(t), the velocity at time t, and the specific solution for v(0) = -1 m/s. c) [5] Evaluate (3x2 — х + 2) dx -1
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![B3:
a)
Differentiate from first principles the function f(x) = x² + 2x – 1.
b)
A particle is moving in a straight line such that at time t (sec) its acceleration is given by
a(t) = 2t – 1 m/s². Derive a general expression for v(t), the velocity at time t, and the specific
solution for v(0) = -1 m/s.
c) [5] Evaluate
(3x2 — х + 2) dx
-1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fab6bb454-81b7-40b3-be3e-b5d3dba4eaa2%2F2fd0849a-7344-4ea6-b0bc-6b413494d77c%2Fts6k3eb_processed.png&w=3840&q=75)
Transcribed Image Text:B3:
a)
Differentiate from first principles the function f(x) = x² + 2x – 1.
b)
A particle is moving in a straight line such that at time t (sec) its acceleration is given by
a(t) = 2t – 1 m/s². Derive a general expression for v(t), the velocity at time t, and the specific
solution for v(0) = -1 m/s.
c) [5] Evaluate
(3x2 — х + 2) dx
-1
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