B.C. IC Solve. Completely to the final form of the 200 Solution as a Fourier Series the heat equation boundary value problem. (homogeneous PDĚ, mixed, X = [0,L] L= 2, k= 4 +₁ zon R 2²u 2u 24, u(o₁t) = 0 u(L₁Z) = 0 u(x, 0) = 1 A homogeneous BC.) - = 0 2x² nut Lond op So not sand of A 10 M dia (start 9-10 N TAS
B.C. IC Solve. Completely to the final form of the 200 Solution as a Fourier Series the heat equation boundary value problem. (homogeneous PDĚ, mixed, X = [0,L] L= 2, k= 4 +₁ zon R 2²u 2u 24, u(o₁t) = 0 u(L₁Z) = 0 u(x, 0) = 1 A homogeneous BC.) - = 0 2x² nut Lond op So not sand of A 10 M dia (start 9-10 N TAS
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:B.C.
Solve. Completely to the final form of the 200
Solution as a Fourier Series the heat.
equation boundary value problem.
IC.
(homogeneous PDĚ, mixed, homogeneous B.C.)
S sul sulod
xe to, L7 L: 2, k=4 t201
2u - R 2²u = 0
3
2t
u(0₁t) = 0
u(Lt) = O
de all st 3.3
u(x,0) = \
JA
:
2x² 10 t pood
op
so rot jand on :/ 10 i dia
9-10
9 + 1 - 2 +
9-15
(4) mei + (as) 223-1)0) + ((s) ora 1 - (0) 205-1) ₁
Fi-Cost
Expert Solution
Step 1: Description about the Problem
The given problem is to find the final form of Fourier series solution for the given heat equation partial differential equation with given initial conditions and boundary conditions.
Given,
ut-kuxx=0,
u(0,t) = u(L,t) = 0
u(x,0) = 1.
Step by step
Solved in 3 steps with 1 images
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