Evaluate the indefinite integral by using the given substitution to reduce the integral to standard form.|12csc (6x)cot (6x)dx, a. u=cot (6x), b. u= csc (6x)a. Using u= cot (6x), 12csc2 (6x)cot (6x)dx = - cot2(6x) + cb. Using u= csc (6x),12csc 2(6x)cot (6x)dx =Hame Evaluate the indefinite infegral by using the groOSALibraryaerailea Teps.TranksCammorn>Expert AnswerStep1Givenb. Using u = csc (6x), 12csc (6x)cot (6x)dx =%3DStep 2We have to use substitution method to evaluate the indefinite integralHoa do you get from this (12)Consider I=[ 12csc² (6x)cot (6x)dx=2 / 6csc (6x)cot (6x)csc (6x)dx To ths ? (2)Now substitute u=csc (6x)differentiate both sidedu=d (csc (6x))=-csc (6x)cot (6x) x d (6x)=-6csc (6x)cot (6x)So l=-2 f uduNow u sin g power rule ( x"dx=S+C--2(4) +c=-cse? (6x) + CPri

Name: Evaluate the indefinite integral by using the given substitution to r
Uploaded: 2024-03-20T06:46:42.000Z
Channel: Bartleby
Description: Evaluate the indefinite integral by using the given substitution to reduce the integral to standard form.|12csc (6x)cot (6x)dx, a. u=cot (6x), b. u= csc (6x)a. Using u= cot (6x), 12csc2 (6x)cot (6x)dx = - cot2(6x) + cb. Using u= csc (6x),12csc 2(6x)