b. The class marks, class boundaries, relative frequency, >CF and CF The frequency distribution table for the data is, 20-26 12 23 19.5-26.5 0.12 12 100 Classes Frequency 27-33 15 30 26.5-33.5 0.15 27 88 20-26 12 34-40 37 37 33.5-40.5 0.37 64 73 27-33 15 41-47 16 44 40,5-47,5 0.16 80 36 48-54 10 51 47.5-54.5 0.1 90 20 34-40 37 55-61 9 58 54.5-61.5 0.09 99 10 41-47 16 62-68 1 65 62.5-67.5 0.01 100 48-54 10 Sum= 100 55-61 9 The Class marks can be calculated by using the formula: 62-68 1 lower lim+upper lim Class marks = The relative frequency can be calculated by using the formula, Subgroup frequency Total frequency Relative Frequency =
Hi, this problem is already reposted. However, not all items were answered before, so pls answer question 2 this time.
PS. Since question 2 is related to question 1, I have also included the latter's answer below. Pls help me with this one. Thank you so much.
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A random sample was taken of the thickness of insulation in transformer windings, and the following thicknesses in millimeters were recorded:
1. a) Make a frequency table for these data starting at lowest lower class limit of 20 and with a class width/ class size of 7.
b) Determine the class marks, class boundaries, relative frequency, <CF, and >CF.
Note: You can use EXCEL.
✓✓ 2.From question 1, Draw the frequency histogram and ogives and make a short description about the shape of distribution.
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