B. Identify the rejection region andsupply its critical value18. Ho: μ-50 Ha: μ*50 a=0.02 n=13o=unknowna. Left-Tailed, -2.179b. Right-Tailed, 2.179c. Two-Tailed, 13.055O d. Two-Tailed, 12.68119. Ho: μ-130 Ha: <130 a=0.01 n=25o-knowna. Left-Tailed, -2.33b. Right-Tailed, 2.33c. Two-Tailed, 12.575d. Two-Tailed, +2.49220. Ho: μ-25 Ha: μ#25 a=0.02 n=5o=unknowna. Left-Tailed, -1.96b. Right-Tailed, 1.96c. Two-Tailed, 13.365d. Two-Tailed, 13.747

Answered: Image /qna-images/answer/9c90e759-376d-407f-891e-e9875fca72d0.jpg

Answered: B. Identify the rejection region and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Testing:H0:μ≤24H0:μ≤24H1:μ>24H1:μ>24Your sample consists of 34 values, with a sample mean of 24.8. Suppose the population standard deviation is known to be 2.36.a) Calculate the value of the test statistic, rounded to 2 decimal places.z=z=b) At α=0.08α=0.08, the rejection region is z<-1.75z<-1.75 z<-1.41z<-1.41 z>1.41z>1.41 z>1.75z>1.75 z<-1.41orz>1.41z<-1.41orz>1.41 z<-1.75orz>1.75z<-1.75orz>1.75 c) The decision is to Reject the null hypothesis Accept the null hypothesis Accept the alternative hypotheis Fail to reject the null hypothesis d) Suppose you mistakenly rejected the null hypothesis in this problem, what type of error is that? Type II Type I
please include all steps.
2,3 D xa lg- Z₂.1's.4² 2.3.0,068 16.0,07.0,7653² 4,7 D x₁ 2axz + bxr lg λew2= λew2 4,7.0,068 2.1,75.10-3 +28,63.10-3
Find the average value of the function f(x) = ex on the interval [0,4]. а. 372.5 O b. 1490 О с. 745 O d. 186.25
7. H0: μ1 ≤ μ2 H1: μ1 > μ2 Test statistic Z = 2.76 Thus, we can not reject H0 if the critical value is: Select one: 2.57 2.87 2.24 1.68
44
23. In a test of hypotheses Ho u = 456 versus H1 : µ < 456, the rejection region is the interval (-00, -1.796], the value of the sample mean computed from a sample of size 12 is = 453, and the value of the test statistic is t = -2.598. The correct decision and justification are: %3D %3D %3D HoM=U56 Hi MLUS6C larim (a) Do not reject Ho because the sample is small. (b) Do not reject Ho because -2.598 < -1.796. (c) Reject Ho because 453 is less than 456. LOS a=.0S (d) Reject H because -2.598 is negative. Ae) Reject Ho because -2.598 lies in the rejection region.
Is there a difference among the 3 treatments in the table below? Test using α = .05 Treatment A Treatment B Treatment C 2 3 2 ∑X2 = 280 2 3 4 G = 60 3 4 5 N = 15 3 5 6 k = 3 5 5 8 SS1 = 6 SS2 = 4 SS3 = 20 What is the value of the critical F boundary? (from the tables)
1. Suppose we model X₁,…, Xn ~ Exp(A) as iid RVs with unknown rate X. Suppose that we observe = 21.79 and n = 100. (a) Conduct a uniformly most powerful test at size a = 0.01 for the test of Ho: A = 1/23 vs H₁: λ=1/22 (b) Recall that the MLE of A is given by Â = 1/. Using the MLE as the test statistic show that for the two-sided test of Ho: λ=1/23 vs H₁: λ1/23 at level a = 0.01 the rejection region is of the form n n {x : Σx₁ ≥C or Σxi ≤ D} i=1 i=1 where C and D are constants to be specified. Hint: Use the hinted result in Assignment 3 Qu(1)(f) to help derive the constants. What is the conclusion in this case? Is the Null rejected? (c) Now, using the likelihood ratio test statistic as the test statistic show that the rejection region for the two sided test of Ho: λ=1/23 vs H₁: λ1/23 can be written as (for some constant C) {2: * Exp(-1/27 ) ≤C} 23 (d) For the setting in (c). Derive an expression for -2 log x(x) and evaluate this given the observed data. (e) For the setting in (c). Given…
The rejection region for a 5% level test of Ho : µ 2 10 versus H1 : µ < 10 is X < 7.9. Find the rejection region for a 1% level test.
Q7. Let {X1, X2, ..., X„} be a random sample from n(µ, 0) where both u and 0 > 0 are unknown. (a) Perform the LRT for Ho : 0 = 0o versus H1 : 0 + 09. (b) Find a size a critical region of the test.
(a) State H 0 and H a identify the claim. (b) Determine the critical value, X^2 0, and the rejection region. (c) Calculate the test statistic.

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