B.) For numbers 1 to 10: Determine if limit of each function exist using the piece-w below x-3 if x < -2 if-2 < x≤0 x² +1 F(x) = 4x + 5 if 0 < x≤ 3 if x > 3 1.) lim f(x) = 2.) lim f(x) = X-3 x→0 3.) lim f(x) = 3.) lim f(x) = x--2 x+1 2x² - 1

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter8: Functions
Section8.1: Concept Of A Function
Problem 100PS
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B.) For numbers 1 to 10: Determine if limit of each function exist using the piece-wise function
below
x - 3
if x < -2
if -2<x<0
x² + 1
F(x) =
if 0 < x≤ 3
if x > 3
1.) lim f(x) =
2.) lim f(x) =
X-3
x→0
3.) lim f(x) =
3.) lim f(x) =
x--2
x-1
5.) lim f(x) =
6.) f (0)=
x→0+
7.) lim f(x) =
8.) f(-2)=
x-2-
9.) lim f(x) =
10.) f (4)=
X-3+
4x + 5
2x² - 1
Transcribed Image Text:B.) For numbers 1 to 10: Determine if limit of each function exist using the piece-wise function below x - 3 if x < -2 if -2<x<0 x² + 1 F(x) = if 0 < x≤ 3 if x > 3 1.) lim f(x) = 2.) lim f(x) = X-3 x→0 3.) lim f(x) = 3.) lim f(x) = x--2 x-1 5.) lim f(x) = 6.) f (0)= x→0+ 7.) lim f(x) = 8.) f(-2)= x-2- 9.) lim f(x) = 10.) f (4)= X-3+ 4x + 5 2x² - 1
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