B. Find y. 2. y = x tan- x – In vx² + 1

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A:

Q: dy Q10., Solve (1+ x²) + y = tan¬1x. dx

A:

Q: Y==(x+1) tant x- Ans:

A: Evaluate it.    1xdydx=tan-1x

Q: Evaluate sec(4x) tan(4x)dx Select one: sec(4x) a. +C sec(z) b. +C 4 C. sec(4x) + C d. 4 sec(4x) + C

A:

Q: A. Differentiate each function. 1. y = 2 sin3 n x 2. у %3D csc(x3 — 1) 1- sin x 3. у %3 1+ sin x

A:

Q: Graph the function y =-2 cos(2x - p)

A: we have to graph  y =-2 cos(2x - p)

Q: B. Find y). 1. y = cosh?x 2. y = x tan-1 x - In vx2 + 1

A:

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A:

Q: Let 4x2 -1 y : tan | dy then dx

A:

Q: Differentiate y= x² cos x tan x

A: To determine:

Q: 3. tan x dx

A: Formula: tan2x=sec2x-1

Q: General Sol. of  y' tanxsin2y= sin2x+sin2y is

A:

Q: B. Find y(4). 1. y = sin 2x tan x csc² 2

A:

Q: Find the equation of the graph given below. Notice that the cosine function is used in the answer…

A: Given that the following graph is                        .

Q: y = cos(-4x)

A: