段階的に解決し、人工知能を使用せず、優れた仕事を行いますご支援ありがとうございましたSOLVE STEP BY STEP IN DIGITAL FORMATDON'T USE AI DON'T USE AI DON'T USE AI DON'T USE AIB. Find the equation of the tangent line.Derived from a function parametrically.2) x = vt2+13) x = Cos xy=14y = sin xt=v38=π-6

Answered: B. Find the equation of the tangent…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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段階的に解決し、人工知能を使用せず、優れた仕事を行います
ご支援ありがとうございました
SOLVE STEP BY STEP IN DIGITAL FORMAT
DON'T USE AI DON'T USE AI DON'T USE AI DON'T USE AI
B. Find the equation of the tangent line.
Derived from a function parametrically.
2) x = vt2+1
3) x = Cos x
y=14
y = sin x
t=v3
8=
π
-6

Expert Solution

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Given that $x equals square root of t squared plus 1 end root space space space a n d space space y equals t to the power of 4 space space space semicolon space t equals square root of 3 space space$

when $t equals square root of 3 space comma space space x equals square root of 3 plus 1 end root equals square root of 4 equals 2 space space space a n d space space space y equals left parenthesis square root of 3 space right parenthesis to the power of 4 equals 3 squared equals 9$

So we have to find the tangent line of the parametric curve at the point $left parenthesis 2 comma 9 right parenthesis$