Answer number 1 to 10. I don't want to waste my money here. B. Evaluate the following.6!1.3!3!9!+7!2.4!3!10!(11!) nAA3.10!-8!%3D%3DO-A10!+3!4.9!-3!Р (11,2)5.Р(10,3). Р(3,4)6.%3DP(9,8)%3DP(7,3)P(8,2)-P(4,2)7.Р(9,8). Р(2,2)8.P(4,3)Р(12,6).P(4,4)9.%3DP(7,4)P(4,4)6!10.3!YA LA

The formula to calculate the permutation is: And, n! = n x (n-1) x (n-2) x .... x 3 x 2 x 1

B. Evaluate the following. 6! 1. 3!3! 9!+7! 2. 4!3! 10!(11!) nA A 3. 10!-8! %3D -A 10!+3! 4. 9!-3! Р(11,2) 5. P(7,3) Р(10,3). Р(3,4) 6. %3D %3D P(9,8) P(8,2)-P(4,2) 7. P(4,4) Р (9,8). Р(2,2) 8. Р(12,6).Р(4,4) 9. P(7,4) P(4,3) = (00 a)NA 6! 10. 3! -

B. Evaluate the following. 6! 1. 3!3! 9!+7! 2. 4!3! 10!(11!) nA A 3. 10!-8! %3D -A 10!+3! 4. 9!-3! Р(11,2) 5. P(7,3) Р(10,3). Р(3,4) 6. %3D %3D P(9,8) P(8,2)-P(4,2) 7. P(4,4) Р (9,8). Р(2,2) 8. Р(12,6).Р(4,4) 9. P(7,4) P(4,3) = (00 a)NA 6! 10. 3! -

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Question

Answer number 1 to 10. I don't want to waste my money here.

B. Evaluate the following.
6!
1.
3!3!
9!+7!
2.
4!3!
10!(11!) nAA
3.
10!-8!
%3D
%3D
O-A
10!+3!
4.
9!-3!
Р (11,2)
5.
Р(10,3). Р(3,4)
6.
%3D
P(9,8)
%3D
P(7,3)
P(8,2)-P(4,2)
7.
Р(9,8). Р(2,2)
8.
P(4,3)
Р(12,6).P(4,4)
9.
%3D
P(7,4)
P(4,4)
6!
10.
3!
YA LA

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