b. Blue Fish acts as an allosteric ligand to control the activity of Seuss1. The binding sites for the substrate of Seuss1 (One Fish) are circled. Use an arrow to show where the allosteric ligand Blue Fish might bind. Explain your choice.

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Chapter1: Biochemistry: An Evolving Science
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**Question 5:**

A metabolic pathway with the end product "Blue fish" is shown below. The enzymes that catalyze each step are shown in italics above each arrow. The committed step is the conversion of One Fish to Two Fish by Seuss1.

**a.** Briefly explain what the "committed step" of a pathway is. Also explain why it makes sense for Seuss1 to catalyze the committed step, and why this step is most likely to be allosterically controlled.

- **Explanation:** The "committed step" in a metabolic pathway is the first irreversible step that commits the substrate to the pathway's end product, effectively regulating the pathway’s flux. It makes sense for Seuss1 to catalyze this step because controlling it allows regulation of the entire pathway, preventing unnecessary accumulation of intermediates. This step is often allosterically controlled to enable fine-tuning of the pathway in response to cellular needs or the presence of end products.

**b.** Blue Fish acts as an allosteric ligand to control the activity of Seuss1. The binding sites for the substrate of Seuss1 (One Fish) are circled. Use an arrow to show where the allosteric ligand Blue Fish might bind. Explain your choice.

- **Explanation:** The allosteric ligand, Blue Fish, would likely bind at a site distinct from the active site, identified by the absence of a circle, in the three-dimensional structure of Seuss1. This binding can induce a conformational change, either enhancing or inhibiting the enzyme's activity, thereby providing a mechanism for feedback inhibition based on the levels of Blue Fish.

**c.** The normal activity of Seuss1 is shown below as the solid line, "Control." (The x-axis, S, is the concentration of the substrate Blue Fish.) Which of the dotted lines do you think shows the activity of Seuss1 in the presence of high concentrations of Blue Fish? Does Blue Fish primarily change Vmax or Km?

- **Diagram Explanation:** The graph depicts enzyme activity plotted as velocity (V) against substrate concentration (S). The solid line indicates the normal activity or control state of Seuss1. The two dotted lines show possible changes in enzyme activity.
  
- **Analysis:** High concentrations of Blue Fish likely correspond to the lower curve, indicating decreased enzyme activity due to feedback inhibition. This suggests that Blue Fish primarily affects Vmax, lowering the maximum rate of
Transcribed Image Text:**Question 5:** A metabolic pathway with the end product "Blue fish" is shown below. The enzymes that catalyze each step are shown in italics above each arrow. The committed step is the conversion of One Fish to Two Fish by Seuss1. **a.** Briefly explain what the "committed step" of a pathway is. Also explain why it makes sense for Seuss1 to catalyze the committed step, and why this step is most likely to be allosterically controlled. - **Explanation:** The "committed step" in a metabolic pathway is the first irreversible step that commits the substrate to the pathway's end product, effectively regulating the pathway’s flux. It makes sense for Seuss1 to catalyze this step because controlling it allows regulation of the entire pathway, preventing unnecessary accumulation of intermediates. This step is often allosterically controlled to enable fine-tuning of the pathway in response to cellular needs or the presence of end products. **b.** Blue Fish acts as an allosteric ligand to control the activity of Seuss1. The binding sites for the substrate of Seuss1 (One Fish) are circled. Use an arrow to show where the allosteric ligand Blue Fish might bind. Explain your choice. - **Explanation:** The allosteric ligand, Blue Fish, would likely bind at a site distinct from the active site, identified by the absence of a circle, in the three-dimensional structure of Seuss1. This binding can induce a conformational change, either enhancing or inhibiting the enzyme's activity, thereby providing a mechanism for feedback inhibition based on the levels of Blue Fish. **c.** The normal activity of Seuss1 is shown below as the solid line, "Control." (The x-axis, S, is the concentration of the substrate Blue Fish.) Which of the dotted lines do you think shows the activity of Seuss1 in the presence of high concentrations of Blue Fish? Does Blue Fish primarily change Vmax or Km? - **Diagram Explanation:** The graph depicts enzyme activity plotted as velocity (V) against substrate concentration (S). The solid line indicates the normal activity or control state of Seuss1. The two dotted lines show possible changes in enzyme activity. - **Analysis:** High concentrations of Blue Fish likely correspond to the lower curve, indicating decreased enzyme activity due to feedback inhibition. This suggests that Blue Fish primarily affects Vmax, lowering the maximum rate of
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