b. An orange contains 71.00% of the recommended daily average of vitamin C (60.0 mg/day). What volume of the DCIP solution, prepared in part a, is needed to titrate the juice from an orange?
b. An orange contains 71.00% of the recommended daily average of vitamin C (60.0 mg/day). What volume of the DCIP solution, prepared in part a, is needed to titrate the juice from an orange?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Ignore part A. Please help me answer part B only. Thank you!
Transcribed Image Text:Titrating Orange juice:
2. Vitamin C (ascorbic acid) and 2,6 dichloroindophenol (DCIP) react according to the
following balanced equation:
НО.
HO
OH
OH
Ascorbic Acid/(Vitamin C)
176.12 g/mole
colorless
DCIP
290.09 g/mole
red- acidic conditions
blue- basic conditions
OH
OH
OH
colorless
HO
CI
colorless
a. We need 500.00 mL of a standard (solution whose concentration is known) solution of
8.000* 10³ M DCIP to titrate an orange juice sample containing Ascorbic acid. How
would you prepare this standard solution?
Hint: First calculate the mass of DCIP that needs to be weighed, and then write a brief
procedure on how a solution is made.
OH
Transcribed Image Text:b. An orange contains 71.00% of the recommended daily average of vitamin C (60.0
mg/day). What volume of the DCIP solution, prepared in part a, is needed to titrate the
juice from an orange?
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