B. A survey on the breakfast drinks of Medical Technology students estimated the percentage of students who drink coffee. From the 1000 students surveyed, 650 said they drink coffee. Construct a 95% confidence interval for the population proportion of Medical Technology students who have coffee in their breakfast.

Q: In a Gallup poll of 804 randomly selected adults living in the 50 U.S. states and the District of…

A: Answer x =466n =804Confidence interval =95%

Q: Suppose a consumer advocacy group wants to conduct a survey to find if the proportion of consumers…

A:

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

A:

Q: A student would like to estimate the proportion of the senior class that plans to attend prom this…

A:

Q: 5.From a sample of 1,000 college students, 28% watch the Super Bowl game each year. Find the margin…

A:

Q: An accounting research firm asked 2100 accountants “Have you ever fudged the numbers before?” and…

A: The sample size is 2100 and 40% responded yes.

Q: a survey of 3088 adults aged 57 through 85​ years, it was found that 87.1​% of them used at least…

A: The formula for computing confidence interval is,  n is the sample size and P is the proportion.

Q: In a survey of 1,200 social media users, 56% said it is not okay to be friends with your boss.…

A:

Q: You observe 60 customers at a coffee shop, and 82% of them tip. What is the 95% confidence interval…

A: Given : You observe 60 customers at a coffee shop, and 82% of them tip.

Q: A student polls his school to see if students in the school district are for or against the new…

A: Given: n=600 and x=480. Then,p^=xn=480600=0.8

Q: researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 520…

A:

Q: In a survey of 2282​ adults, 749 say they believe in UFOs. Construct a 90% confidence interval for…

A:

Q: 2. In 2001, a Gallup poll surveyed 1016 households in the U.S about their pets. Of those surveyed,…

A: Given;n = 1016 x = 599p' = xn=5991016=0.58957

Q: Out of all the students that attend Yale University, 1,982 were selected to participate in a school…

A:

Q: A department chair wanted to know whose students performed better on a common pass/fail final exam:…

A: p1 :  proportion of students passed in smith's  class p2 :  proportion of students passed in Jones's…

Q: Several years ago, 39% of parents who had children in grades K-12 were satisfied with the quality of…

A:

Q: Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying…

A: Solution: Given that, Estimate the proportion of students on her campus who eat cauliflower n=20 #…

Q: 324 out of a simple random sample of 400 students hated their online math course. Find a 99%…

A: Given: Number of students that hated the online math course (y) = 324 Number of students (n) = 400…

Q: Google is studying the quality of results returned by an upgraded version of its search engine.…

A: From the given information, it can be observed that x = 23 and n =100.

Q: A survey found that 33 of 66 randomly selected women and 37 of 66 randomly selected men follow a…

A:

Q: Facebook would like to study the demographics of the individuals that utilize their platform. Their…

A: a. The sample size n= 455. Out of the 455 Facebook users 63 were teenagers. The sample proportion is…

Q: A survey of 800 women shoppers found that 15% of them shop on impulse.  What is the 95% confidence…

A: n = 800p^ = 0.1595% CI for p = ?

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: A survey of 127 patients in a particular hospital determined that 54% of them felt that they were…

A: The sample proportion of patients felt they were receiving excellent care (p-cap) is 0.54. The…

Q: Of 254 randomly selected medical students, 25 said that they planned to work in a rural community.…

A: It is given that, the number of students said that they planned to work in natural community   (x)…

Q: Leana is interested in the proportion of people who live in her area who own a dog. She randomly…

A: Suppose p is the population proportion of people who live within one mile of Person L’s home who own…

Q: In a survey of 3332 adults aged 57 through 85​ years, it was found that 80.7​% of them used at least…

A:

Q: In a survey of 1,626,773 U.S. adults, 49,311 personally identified as lesbian, gay, bisexual, or…

A:

Q: Use the sample data in Example #1 (picture) and a technology tool to construct 75%, 85%, and 99%…

A: Given:

Q: A marketing survey involves product recognition in New York and California. Of 558 New Yorkers…

A:

Q: A marketing study by Ford Motor Company finds that 320 of the 650 buyers of compact cars were women.…

A: Let the population proportion of women who bought compact cars be P Given:         Sample size n =…

Q: Find 90% confidence interval for the true proportion of all medical students who plan to work in a…

A: Given : Sample Size, n = 300 Number of successes, x = 30

Q: The figure to the right shows the results of a survey in which 997 adults from Country​ A, 1022…

A: Given data For country A n = 997

Q: Construct a 95% confidence interval for the proportion of college students who say they own their…

A: Given : n=410 , X=155  , α=0.05 We want to find the 95% confidence interval for the proportion of…

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: According to a telephone survey of adults, 86% of homeowners said that owning a home was a good…

A: From the given information, According to a telephone survey of adults, 86% of homeowners said that…

Q: Assume a nationwide random survey of 800 adults asked about attitudes toward “alternative medicine”…

A: We have given that,  Sample size (n) = 800 and Favorable cases (X) =448 Then,  We will find the 99%…

Q: At one large college, 1867 out of the 2500 students surveyed said they plan to take another science…

A: The known values are, p^=1,867/2,500=0.7468, n=2,500. Using standard normal table, the critical…

Q: The pizza Shop wanted to determine what proportion of its customers ordered an only cheese pizza.…

A:

Q: A university planner wants to determine the proportion of undergraduate students who plan to attend…

A:

Q: Researchers are interested in the average heart rate of male college students. Assume a random…

A: Here, the sample proportion, p^ is 0.65 =130200 and the sample size, n  is 200. Using standard…

Q: Construct and interpret a 95% confidence interval

A: According to a recent random survey of 3,728 US adults, 1,939 report using their cell phones to play…

Q: A Gallup poll of 1487 adults showed that 43% of the respondents have Facebook pages.  Construct a…

A: Confidence Interval: In statistics, we can say a range of values of the specified population…