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B. A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?

B. A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Problem Statement** A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product? --- To calculate the specific rotation (\([\alpha]\)) of the natural product, use the formula: \[ [\alpha] = \frac{\alpha}{l \cdot c} \] Where: - \([\alpha]\) is the specific rotation. - \(\alpha\) is the observed rotation (+2.57°). - \(l\) is the path length of the tube in decimeters (50 cm = 5.0 dm). - \(c\) is the concentration of the solution in grams per milliliter (2.0 g/10 mL = 0.2 g/mL). Substitute the values into the formula to find the specific rotation.
Transcribed Image Text:**Problem Statement** A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product? --- To calculate the specific rotation (\([\alpha]\)) of the natural product, use the formula: \[ [\alpha] = \frac{\alpha}{l \cdot c} \] Where: - \([\alpha]\) is the specific rotation. - \(\alpha\) is the observed rotation (+2.57°). - \(l\) is the path length of the tube in decimeters (50 cm = 5.0 dm). - \(c\) is the concentration of the solution in grams per milliliter (2.0 g/10 mL = 0.2 g/mL). Substitute the values into the formula to find the specific rotation.
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