B. A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?
B. A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement**
A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?
---
To calculate the specific rotation (\([\alpha]\)) of the natural product, use the formula:
\[
[\alpha] = \frac{\alpha}{l \cdot c}
\]
Where:
- \([\alpha]\) is the specific rotation.
- \(\alpha\) is the observed rotation (+2.57°).
- \(l\) is the path length of the tube in decimeters (50 cm = 5.0 dm).
- \(c\) is the concentration of the solution in grams per milliliter (2.0 g/10 mL = 0.2 g/mL).
Substitute the values into the formula to find the specific rotation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F32eaab5a-5dd5-4188-9d2c-5f1c072f447d%2F91d66832-d640-48d1-84ba-729a0d8ebc45%2Fdwg8lb_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement**
A newly isolated natural product was shown to be optically active. If a solution of 2.0 g in 10 mL of ethanol in a 50 cm tube gives a rotation of +2.57°, what is the specific rotation of this natural product?
---
To calculate the specific rotation (\([\alpha]\)) of the natural product, use the formula:
\[
[\alpha] = \frac{\alpha}{l \cdot c}
\]
Where:
- \([\alpha]\) is the specific rotation.
- \(\alpha\) is the observed rotation (+2.57°).
- \(l\) is the path length of the tube in decimeters (50 cm = 5.0 dm).
- \(c\) is the concentration of the solution in grams per milliliter (2.0 g/10 mL = 0.2 g/mL).
Substitute the values into the formula to find the specific rotation.
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