B. 30°

Q: The springs on the rope assembly are originally unstretched when theta = 0°. Determine the tension…

A: Given data Force (F) = 400 N

Q: If the mass of the flowerpot is 65 kg, calculate the tension generated in every cable for…

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Q: Problem 2. Consider the frame loaded as shown. If the reaction force at the roller at F is 250N,…

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Q: The boom AB is held in equilibrium by a ball-and-socket joint A and a pulley and cord system as…

A: The force F is -2200 k⇀ lb

Q: The following system is in equilibrium. Draw the free-body diagram of the frame and apply the…

A:

Q: The 500-kg crate is supported by the three cables. Find the tension in cables AD, BD and CD.

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Q: 1.If cable CB is subjected to a tension that is twice that of cable CA, determine the angle 0 for…

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Q: d 0- D

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Q: 1m DS

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Q: The 9500-lb pipe is supported by three cables. Determine the force in each cable for equilibrium of…

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Q: Determine the tension developed in each cable for equilibrium of the 300-lb crate. CG 3 ft 6 ft 3 ft…

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Q: If the mass of the flowerpot is 65 kg, calculate the tension generated in every cable for…

A: Solution:

Q: Point D is held in equilibrium by the cables as shown. If the force of F is 305 lb, then what is the…

A: Point D is held in equilibrium by the cables as shown. If the force of F is 305 lb.To Find-The…

Q: 5. Determine the tension developed in cable AD to have the tower in equilibrium if the tension in…

A: Find the position vector of points  A, B, C and D: rA=30 k^rB=10 i^-15 j^rC=-15 i^-10 j^rD=12.5 j^…

Q: P2 B. C 4 m D -3 m- -3 m- -3 m- -3 m-

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Q: 3) If cable CD has 100 N of tension, determine the tension developed in the other two cables and the…

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Q: The 6-m pole ABC is acted upon by a 460-N force, P, as shown in the figure. The pole is held by a…

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Q: A uniform steel ring 600 mm in diameter has a mass of 100 kg and is supported by three cables, each…

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Q: Both pulleys are fixed to the shaft and as the shaft turns with constant angular velocity, the power…

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Q: The traffic light has a mass of 15 kg, and if it is held in the equilibrium position shown by the…

A: To find: The tension in the cable AB. Given: The mass of the traffic light is m=15 kg. The unit…

Q: If F = 810 N , determine the tension developed in cables AB, AC, and AD

A: Given that: F = 810 N In the given configuration, it is required to determine the forces developed…

Q: If the plate is to remain in equilibrium, find the tension for all the three cable that supports the…

A: Free body diagram of the load is shown in the figure. Dimensions of the plate are as shown in the…

Q: The ring weighs 6 lbf and is in equilibrium. The force F1 = 4.5 lbf. Determine the force F2 and the…

A: As per given question  Force f1=4.5 lbf And angle =30° We have to determine force f2 and angle α

Q: Q3. The lamp has a weight of (20 - 40 N) and is supported by the six cords connected together as…

A: Please find the tension and angle for maximum weight of the lamp. Given: The maximum and minimum…

Q: THE 600 lb CRATE IS SUPPORTED BY THE THREE CABLES. FIND THE TENSION IN EACH CABL

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Q: If the tension developed in each of the three cables, AB, CD, and EF, is the same, find the location…

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Q: Find the value of each of the angles β and α that keep the system of forces in equilibrium

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Q: A 10 m y 16 kN/m 10 m B T 2 m -X

A: w0= 16 kN/mL= 10 mLtotal= 10+10= 20 mh= 2m

Q: Point D is held in equilibrium by the cables as shown. If the force of F is 296 lb, then what is the…

A: Given: Force, F= 296 lbSystem with distances and forceTo find:Tension in cable CD in lb

Q: magnitude of the vertical reaction force developed at the point B

A: Given; Two steel truss members, AC and BC, each having cross-sectional area=100 mm2It is subjected…

Q: 30 2f- 6 ft-

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Q: 4. If cable CB is subjected to a tension that is twice that of cable CA, determine the angle e for…

A: Given data Mass of cylinder = 10kg

Q: Take F = 310 N and d = 1.0 m Determine the force in cable AC and AB needed to hold the 24-kg ball D…

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Q: F1 α 30°

A: Let W = Weight of ring =5N F1 =4.5N By using law of equilibrium  ΣFx = 0 F1cos30° - F2cosα =0…