(b) You measure the data given on the right for the concentration of ethanol in a patient's blood. Write down the solution to the differential equation from part (a) in terms of co and ko- t (hrs) c(t) (g/liter) 2.0 1.8 c(t) = Co - kot Calculate the parameters c, and k, that fit the model to this data. Co = and ko = (Type integers or decimal rounded to three decimal places as needed.) 2.

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Chapter2: Second-order Linear Odes
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**Modeling Ethanol Concentration in Blood**

In this exercise, you are given data regarding the concentration of ethanol in a patient's blood over time. Your goal is to derive parameters for the equation modeling this concentration.

### Given:
A table showing the concentration of ethanol at different times:

| t (hrs) | c(t) (g/liter) |
|---------|----------------|
| 0       | 2.0            |
| 2       | 1.8            |

### Task:
You need to write down the solution to the differential equation, expressed in terms of \( c_0 \) and \( k_0 \).

The concentration function is described by:
\[
c(t) = c_0 - k_0 t
\]

### Objective:
Calculate the parameters \( c_0 \) and \( k_0 \) that best fit the given data. These parameters should be entered as integers or decimals rounded to three decimal places.

- **\( c_0 \) =** [Input Required]
- **\( k_0 \) =** [Input Required]

This exercise helps in understanding how to apply linear modeling to biological processes such as the metabolism of substances in the body.
Transcribed Image Text:**Modeling Ethanol Concentration in Blood** In this exercise, you are given data regarding the concentration of ethanol in a patient's blood over time. Your goal is to derive parameters for the equation modeling this concentration. ### Given: A table showing the concentration of ethanol at different times: | t (hrs) | c(t) (g/liter) | |---------|----------------| | 0 | 2.0 | | 2 | 1.8 | ### Task: You need to write down the solution to the differential equation, expressed in terms of \( c_0 \) and \( k_0 \). The concentration function is described by: \[ c(t) = c_0 - k_0 t \] ### Objective: Calculate the parameters \( c_0 \) and \( k_0 \) that best fit the given data. These parameters should be entered as integers or decimals rounded to three decimal places. - **\( c_0 \) =** [Input Required] - **\( k_0 \) =** [Input Required] This exercise helps in understanding how to apply linear modeling to biological processes such as the metabolism of substances in the body.
**Understanding Ethanol Elimination and Differential Equations**

The elimination of ethanol from the blood is typically understood to follow zeroth-order kinetics.

**Question (a):** Explain why the concentration of a drug in the blood satisfies the differential equation \(\frac{dc}{dt} = -k_0\) with \(c(0) = c_0\). Choose the correct answer below.

- **Answer A:** The differential equation for a drug with first-order elimination kinetics is \(\frac{dc}{dt} = A(t) - k_0\). As the drug enters the blood effectively instantaneously, there is no further absorption after time \(t = 0\), so \(A(t) = 0\). Thus, \(\frac{dc}{dt} = -k_0\).

In this explanation, we assume that after the drug enters the bloodstream, it is no longer absorbed, and the rate of change in concentration is solely dictated by the elimination constant, \(k_0\), resulting in a constant rate of elimination, characteristic of zeroth-order kinetics.
Transcribed Image Text:**Understanding Ethanol Elimination and Differential Equations** The elimination of ethanol from the blood is typically understood to follow zeroth-order kinetics. **Question (a):** Explain why the concentration of a drug in the blood satisfies the differential equation \(\frac{dc}{dt} = -k_0\) with \(c(0) = c_0\). Choose the correct answer below. - **Answer A:** The differential equation for a drug with first-order elimination kinetics is \(\frac{dc}{dt} = A(t) - k_0\). As the drug enters the blood effectively instantaneously, there is no further absorption after time \(t = 0\), so \(A(t) = 0\). Thus, \(\frac{dc}{dt} = -k_0\). In this explanation, we assume that after the drug enters the bloodstream, it is no longer absorbed, and the rate of change in concentration is solely dictated by the elimination constant, \(k_0\), resulting in a constant rate of elimination, characteristic of zeroth-order kinetics.
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