b) y = vs3 + 1 dy dt
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the derivative of this function but Do Not Simplify
![The equation given is:
\[ b) \quad y = \sqrt{s^3 + 1} \]
The task is to find the derivative of \( y \) with respect to \( t \), represented as:
\[ \frac{dy}{dt} = \, \]
This problem is likely part of a section on differentiation and chain rule applications. It starts with the function \( y \) expressed in terms of \( s \). We aim to find how \( y \) changes as \( t \) changes, which involves implicit differentiation if \( s \) is also a function of \( t \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F28b0c599-bbea-4dfa-aec4-e0091988eaa4%2Fe11418db-0048-46bf-bdbe-52e5198abcc3%2Fx4x9w4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The equation given is:
\[ b) \quad y = \sqrt{s^3 + 1} \]
The task is to find the derivative of \( y \) with respect to \( t \), represented as:
\[ \frac{dy}{dt} = \, \]
This problem is likely part of a section on differentiation and chain rule applications. It starts with the function \( y \) expressed in terms of \( s \). We aim to find how \( y \) changes as \( t \) changes, which involves implicit differentiation if \( s \) is also a function of \( t \).
Expert Solution
Step 1
We used the chain rule.
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