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(b) xy' = 2y + x³ cos x x 500 ₂x = L = ² - ₁ k P(x) = -2/² Q(x) = x² cost dix) = -Sdx e ^4 = = = = = [[√x ²³ x² co₂x dx+c] Y=x² [SINX+C]

(b) xy' = 2y + x³ cos x x 500 ₂x = L = ² - ₁ k P(x) = -2/² Q(x) = x² cost dix) = -Sdx e ^4 = = = = = [[√x ²³ x² co₂x dx+c] Y=x² [SINX+C]

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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I am confused how they found the general solution to this problem. What is the purpose of using P(x) and Q(x) and why is there e^(-integral(2/x)) when solving for the general solution? 

 

I would appreciate a more detailed answer than the one in this answer key. Thank you in advance!

(b) xy = 2y + x³ cos x y² - 22/1 2 =X COSX x P(x) == /²/²/²_Q(x)=x²³² cost dilx) - -S3dx e -2 x 4 = = S =+=+=[√x ² x ² c05x dx +c] 2 cost Y=x² [SINZ+c]
Transcribed Image Text:(b) xy = 2y + x³ cos x y² - 22/1 2 =X COSX x P(x) == /²/²/²_Q(x)=x²³² cost dilx) - -S3dx e -2 x 4 = = S =+=+=[√x ² x ² c05x dx +c] 2 cost Y=x² [SINZ+c]
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