B: write a program to find n factorial (n!)
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- Which of the following is the termination condition in the following recursive function, assuming N only accepts integer values? def xxx(N): if (N 4 b. N > 5 C. N<4 D. N< 5True or False: Asymptotically analyze the expression below. n²(1 +sqrt(n)) = O(n² log n) O True O FalseJava, I am not displaying my results correct. It should add up the digits in the string. input string |result for the sumIt Recursion functions and a findMax function that finds the largest number in a string "1d2d3d" | 6 total "55" |10 total "xx" | 0 total "12x8" |12 Max number "012x88" |88 Max Number "012x88ttttt9xe33ppp100" |100 Max Number public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be…
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- language: Python Problem: Write a recursive function reverse(sentence) for reversing a sentence. For example, reverse('Who let the dogs out?') will return '?tuo sgod eht tel ohW'. Also write a test case in the program to prove the function given works.//Can you please debug this program. Thank you #include<stdio.h>#include<stdlib.h> //This function takes n and k and computes n using Pascal’s Rule.long choose(int n, int k); //This functions below create a memoization table containing//long values of dimension (n+1)×(k+1) long chooseWithMemoization(int n, int k); //This is a new recursive function that also takes the table as a parameter.//When the function needs to compute (n , k )it checks the table first, and//if the value has already been comput(is not -1) then it returns that value. long chooseWithMemoizationRecursive(int n, int k, long **tableau); int main(int argc, char **argv) {//variable declaration int n; int k; scanf("%d",&n); scanf("%d",&k ); long choice = -1;//printing out the out put choice = chooseWithMemoization(n,k); printf("choose(%d,%d) = %ld\n", n, k, choice); return 0;} /** * This function takes n and k and computes n using Pascal’s Rule.*/long choose(int…Please type answer no write by hend.