(b) What is P(X ≤ 0.7) [i.e., F(0.7)]? (Round your answer to four decimal places.) 0.1960 (c) Using the cdf from (a), what is P(0.45 < x≤ 0.7)? (Round your answer to four decimal places.) 0.1869 What is P(0.45 ≤ x ≤ 0.7)? (Round your answer to four decimal places.) 0.1869 (d) What is the 75th percentile of the distribution? (Round your answer to four decimal places.) 7 0.4207 x (e) Compute E(X) and ox. (Round your answers to four decimal places.) E(X)= 0.8 0.1206 (f) What is the probability that X is more than 1 standard deviation from its mean value? (Round your answer to four decimal places.) 10 0.1551 x

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## Probability Density Function (PDF) and Cumulative Distribution Function (CDF)

### PDF Explanation

Let \( X \) denote the amount of space occupied by an article in a 1-t\(^2\) packing container. The probability density function (pdf) of \( X \) is defined as:

\[ f(x) = 
  \begin{cases} 
   12x^2(1-x) & \text{for } 0 < x < 1\\
   0 & \text{otherwise}
  \end{cases}
\]

### Graphing the PDF

The graphs shown for the PDF \( f(x) \) illustrate the function over the interval \( 0 < x < 1 \). Various graph shapes are proposed, and the correct graph is indicated with a check mark (✓). This graph shows a peak within the range and zero outside \( 0 < x < 1 \).

### CDF Explanation

The cumulative distribution function (CDF) \( F(x) \) is derived as follows:

\[ F(x) = 
  \begin{cases} 
   0 & \text{for } x < 0\\
   -8x^3 + 9x^2 & \text{for } 0 \leq x \leq 1\\
   1 & \text{for } x > 1
  \end{cases}
\]

### Graphing the CDF

Various graphs propose the shape for \( F(x) \). The correct graph, marked with a check (✗ indicates incorrect), shows a gradual increase from 0 to 1 over the interval \( 0 \leq x \leq 1 \) and remains constant outside this interval.

### Questions and Answers

(b) **Probability \( P(X \leq 0.7) \):** Given as \( F(0.7) \), the answer is **0.9600**.

(c) **Probability \( P(0.45 < X \leq 0.7) \):** Using the CDF, the answer is **0.1889**.

(d) **Probability \( P(0.45 \leq X \leq 0.7) \):** The given result matches (c): **0.1889**.

(e) **75th Percentile of the Distribution:** The answer is **0.
Transcribed Image Text:## Probability Density Function (PDF) and Cumulative Distribution Function (CDF) ### PDF Explanation Let \( X \) denote the amount of space occupied by an article in a 1-t\(^2\) packing container. The probability density function (pdf) of \( X \) is defined as: \[ f(x) = \begin{cases} 12x^2(1-x) & \text{for } 0 < x < 1\\ 0 & \text{otherwise} \end{cases} \] ### Graphing the PDF The graphs shown for the PDF \( f(x) \) illustrate the function over the interval \( 0 < x < 1 \). Various graph shapes are proposed, and the correct graph is indicated with a check mark (✓). This graph shows a peak within the range and zero outside \( 0 < x < 1 \). ### CDF Explanation The cumulative distribution function (CDF) \( F(x) \) is derived as follows: \[ F(x) = \begin{cases} 0 & \text{for } x < 0\\ -8x^3 + 9x^2 & \text{for } 0 \leq x \leq 1\\ 1 & \text{for } x > 1 \end{cases} \] ### Graphing the CDF Various graphs propose the shape for \( F(x) \). The correct graph, marked with a check (✗ indicates incorrect), shows a gradual increase from 0 to 1 over the interval \( 0 \leq x \leq 1 \) and remains constant outside this interval. ### Questions and Answers (b) **Probability \( P(X \leq 0.7) \):** Given as \( F(0.7) \), the answer is **0.9600**. (c) **Probability \( P(0.45 < X \leq 0.7) \):** Using the CDF, the answer is **0.1889**. (d) **Probability \( P(0.45 \leq X \leq 0.7) \):** The given result matches (c): **0.1889**. (e) **75th Percentile of the Distribution:** The answer is **0.
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