Question #6 Part C # Standard Normal Distribution TableThis document provides a comprehensive standard normal distribution table used to find probabilities related to the standard normal curve, a crucial concept in statistics.## DescriptionThe table is divided into two sections, each displaying areas under the normal curve for positive and negative z-scores. These areas represent the probability that a standard normal random variable is less than the given z-value. The table includes:- **Z-scores**: These values are represented in the leftmost column. Each entry is expressed with one decimal place.- **Probabilities**: The intersecting values within the table correspond to the area (probability) under the curve to the left of the given z-score. Each column header from 0.00 to 0.09 adds a hundredth to the z-score in the row.### Graphical ExplanationTwo small graphs above the tables illustrate the normal curve with shaded areas:- **Curve**: Represents the bell-shaped, standard normal distribution.- **Shaded Area**: Represents the cumulative probability from the z-score to the left, matching the tabular values. The graph visually demonstrates how the area under the curve corresponds to the values found in the table.## UsageTo find the probability associated with a specific z-score:1. Locate the z-score row (e.g., 0.1) and the column with the correct hundredths place (e.g., 0.03).2. Intersect the row and column to find the probability.3. Use the left table for positive z-scores and the right table for negative z-scores.The table is essential for statistical analysis, including hypothesis testing and confidence interval construction. **Text Transcription:**A random sample of 1017 adults in a certain large country was asked "Do you pretty much think televisions are a necessity or a luxury you could do without?" Of the 1017 adults surveyed, 515 indicated that televisions are a luxury they could do without. Complete parts (a) through (e) below.- Click here to view the standard normal distribution table (page 1).- Click here to view the standard normal distribution table (page 2).**(b) Verify that the requirements for constructing a confidence interval about p are satisfied.**The sample is stated to be a simple random sample, the value of \( \hat{p}(1-\hat{p}) \) is 254.213, which is greater than or equal to 10, and the sample size can be assumed to be less than or equal to 5% of the population size. (Round to three decimal places as needed.)**(c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice.**(Type integers or decimals rounded to three decimal places as needed. Use ascending order.)- \( \bigcirc \) A. There is a \(\_\_\_\_\_\_\) % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between \(\_\_\_\_\_\_\) and \(\_\_\_\_\_\_\).- \( \bigcirc \) B. We are \(\_\_\_\_\_\_\) % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between \(\_\_\_\_\_\_\) and \(\_\_\_\_\_\_\).

Given Data Sample Size, n = 1017 Number of successes, x = 515.0 confidence level,c= 0.95solution : Significance level, α =1- 0.95 = 0.05 Point estimate p̂ = x/n = 515.0 / 1017 = 0.506391 Critical value critical value at α = 0.05 is Zα/2 = 1.96 ....from the standard normal distribution table 95% confidence interval = 0.506391 ± 1.96 x √ {( 0.506391 (1- 0.506391 )/ 1017 } = 0.506391 ± 0.030728 =( 0.506391 - 0.030728 , 0.506391 + 0.030728 ) =( 0.476 , 0.537 ) We are 95 % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between 0.476 and 0.537

Math

Statistics

(b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample is stated to be a simple random sample, the value of np(1-p) is 254.213, which is greater than or equal to 10, and the sample size can be assumed to be less than or equal to 5% of the population size. (Round to three decimal places as needed.) (c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) O A. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between and O B. We are % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and

(b) Verify that the requirements for constructing a confidence interval about p are satisfied. The sample is stated to be a simple random sample, the value of np(1-p) is 254.213, which is greater than or equal to 10, and the sample size can be assumed to be less than or equal to 5% of the population size. (Round to three decimal places as needed.) (c) Construct and interpret a 95% confidence interval for the population proportion of adults in the country who believe that televisions are a luxury they could do without. Select the correct choice below and fill in any answer boxes within your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) O A. There is a % probability the proportion of adults in the country who believe that televisions are a luxury they could do without is between and O B. We are % confident the proportion of adults in the country who believe that televisions are a luxury they could do without is between and

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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