(b) The Fibonacci numbers for n 0, 1,...are defined as follows.fib (0)-0fib (1) 1:fib (n) fib (n- 1) + fib (n - 2):Consider the following piece of code that calculates the Fibonacci numbers.int fib ( int n){if (n is 0)return 0else if (n is 1)return 1elsereturn fib (n- 1)+ fib (n- 2)What is the worst-case complexity of the above code?

Fibonacci series: fib(n) = fib(n-1) + fib(n-2) → for n > 1fib(n) = 1→ for n = 0, 1 Fibonacci can…

(b) The Fibonacci numbers for n-0, 1,.. are defined as follows. fib (0)-0 fib (1)-1: fib (n)-fib (n- 1) + fib (n - 2): Consider the following piece of code that calculates the Fibonacci nu int fib ( int n){ if (n is 0) return 0 else if (n is 1) return 1 else return fib (n - 1) + fib (n - 2) nat is the worst-case complexity of the above code?

(b) The Fibonacci numbers for n-0, 1,.. are defined as follows. fib (0)-0 fib (1)-1: fib (n)-fib (n- 1) + fib (n - 2): Consider the following piece of code that calculates the Fibonacci nu int fib ( int n){ if (n is 0) return 0 else if (n is 1) return 1 else return fib (n - 1) + fib (n - 2) nat is the worst-case complexity of the above code?

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

X3: inlTo10 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10.
imple java code for beginner Write a method largest is used to determine the - largest number from a set of numbers. - Example: - Given 12, 45, 23, 11, 38, 29, 15, 10, 34 * The largest is 45 simple java code dont use array we did not take it yet
8. Know how to do these, to trace functions like these and to debug functions like these: // recursive power , compute xn int exp(int x, int n){ if(n== return return *exp( ); } void main(){ int a,b; cin >>a>>b; cout>a; rev_print(a); }
mergeAndRemove(int[], int[]) This is a public static function that takes a int[] and int[] for the parameters and returns an int[]. Given two arrays of integers. Your job is to combine them into a single array and remove any duplicates, finally return the merged array.
please code in python You place a pawn at the top left corner of an n-by-n chess board, labeled (0,0). For each move, you have a choice: move the pawn down a single space, or move the pawn down one space and right one space. That is, if the pawn is at position (i,j), you can move the pawn to (i+1,j) or (i+1, j+1). Ask the user for the size of a chessboard, n (integer). Find the number of different paths starting from (0,0) that the pawn could take to reach each position on the chess board. For example, there are two different paths the pawn can take to reach (2,1). Look at the diagrams below to convince yourself of this. You can see the four paths that you can take by move 2. Start -> Move 1 -> Move 2 (0,0) -> (1,0) -> (2,1) (0,0) -> (1,0) -> (2,0) (0,0) -> (1,1) -> (2,1) (0,0) -> (1,1) -> (2,2) Print the board with the number of ways to reach each square labeled as shown below. For example: Enter a board size: 4 1 0 0 0 1 1 0 0 1 2 1 0 1 3 3 1
Lab Goal : This lab was designed to teach you more about recursion. Lab Description : Take a number and recursively determine how many of its digits are even. Return the count of the even digits in each number. % might prove useful to take the number apart digit by digit Sample Data : 453211145322224532714246813579 Sample Output : 23540
# We have small bags of cement (10 kilograms each)# We have big bags of cement (50 kilograms each)# Return the number of each of the bags to use,# assuming we always use big bags before small bags.# Return -1 for each if it can't be done.## Oh, and there 4 errors in the main() function# Happy Debugging! import random def main():keep_going = "y" while keepgoing.upper() == "Y": small_bags = random.randint(5,20) big_bags = random.randint(1,5) goal = random.randint(60,350,10) small_used, big_used = make_cemont(small_bags, big_bags, gaol)if small_used == -1: print("Sorry, we can't reach", goal, "kilograms with", small_bags, "small bags and", big_bags, "big bags.")else: print("Goal", goal, "kilograms achieved!") print("Small bags:", small_used, "out of", small_bags) print(" Big bags:", big_used, "out of", big_bags) another_round = input("Try again (y/n)?: ")def make_cement(small_bags_supplied, big_bags_supplied,…
CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021
Correct answer will be upvoted else Multiple Downvoted. Computer science. you can choose two indices x and y (x≠y) and set ax=⌈axay⌉ (ceiling function). Your goal is to make array a consist of n−1 ones and 1 two in no more than n+5 steps. Note that you don't have to minimize the number of steps. Input The first line contains a single integer t (1≤t≤1000) — the number of test cases. The first and only line of each test case contains the single integer n (3≤n≤2⋅105) — the length of array a. It's guaranteed that the sum of n over test cases doesn't exceed 2⋅105. Output For each test case, print the sequence of operations that will make a as n−1 ones and 1 two in the following format: firstly, print one integer m (m≤n+5) — the number of operations; next print m pairs of integers x and y (1≤x,y≤n; x≠y) (x may be greater or less than y) — the indices of the corresponding operation. It can be proven that for the given constraints it's always possible to find a correct sequence…
Homework 5 CMP 167: Programming Methods I Lehman College, City University of New York Homework 5-1 I Write a program with a loop that iterates as long as an int variable called num is less or equal to 50. Num must be initialized with a value of 1 and incremented by 1 with each iteration. Each iteration of the loop must print all appropriate sentences for that number according to the following 1. If num is odd, output: num is an odd number 2. If num is even, output: num is an even number output: num is divisible by 2 3. If num is divisible by 2, 4. If num is divisible by 5, output: num is divisible by 5 5. If num is divisible by 8, output: num is divisible by 8 6. If num is divisible by 11, output: num is divisible by 11 Please note that your class should be named FirstLoop.
int getMax(int arr[], int n) { intmx=arr[0]; for (inti=1; i<n; i++) if (arr[i] >mx) mx=arr[i]; returnmx; } Can u give me the code for this one as well....this is the first function and countsort is the second
Х3: inlTol0 Write a function in Java that implements the following logic: Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10. Your Answer: 1 public boolean in1To10(int n, boolean outsideMode) 2 { 3 } H N M