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(b) The common emitter amplifier is shown in Fig. 2(b). Assume that the BJT has small-signal high frequency parameters, gm = 2 mA/V, r = 2.5 kn, ro = 25 kn, Cr = 20 pF and Cu = 12 pF. %3D i. Draw the Miller equivalent circuit ii. Determine the Miller capacitance, CM- ii. Calculate the cutoff frequency, fr of the transistor +10V RC 4k 60k C2 R1 v, 10uF Rs wHE 5k 10uF RL 2k R2 40k RE 1k Cs 50uF -10V Fig. 2(b) ww

(b) The common emitter amplifier is shown in Fig. 2(b). Assume that the BJT has small-signal high frequency parameters, gm = 2 mA/V, r = 2.5 kn, ro = 25 kn, Cr = 20 pF and Cu = 12 pF. %3D i. Draw the Miller equivalent circuit ii. Determine the Miller capacitance, CM- ii. Calculate the cutoff frequency, fr of the transistor +10V RC 4k 60k C2 R1 v, 10uF Rs wHE 5k 10uF RL 2k R2 40k RE 1k Cs 50uF -10V Fig. 2(b) ww

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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(b) The common emitter amplifier is shown in Fig. 2(b). Assume that the BJT has small-signal high frequency parameters, gm = 2 mA/V, r = 2.5 kn, ro = 25 kN, Cr = 20 pF and Cu = 12 pF. i. Draw the Miller equivalent circuit ii. Determine the Miller capacitance, CM- iii. Calculate the cutoff frequency, fr of the transistor 9 +10V RC 4k 60k Cc2 R1 HE O v, 10uF Rs wwHE 5k 10uF 2k R2 40k RE 1k: Cs 50UF -10V Fig. 2(b) ww ww ww
Transcribed Image Text:(b) The common emitter amplifier is shown in Fig. 2(b). Assume that the BJT has small-signal high frequency parameters, gm = 2 mA/V, r = 2.5 kn, ro = 25 kN, Cr = 20 pF and Cu = 12 pF. i. Draw the Miller equivalent circuit ii. Determine the Miller capacitance, CM- iii. Calculate the cutoff frequency, fr of the transistor 9 +10V RC 4k 60k Cc2 R1 HE O v, 10uF Rs wwHE 5k 10uF 2k R2 40k RE 1k: Cs 50UF -10V Fig. 2(b) ww ww ww
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