### Problem Statement:**Scenario:**A 40 kg crate falls off a forklift moving at 3 m/s and slides along the warehouse floor, coming to rest after covering a distance of 2.5 m.**Given Data:**- Mass of the crate (\(m\)): 40 kg- Initial velocity (\(v_i\)): 3 m/s- Distance traveled before stopping (\(d\)): 2.5 m- Coefficient of kinetic friction (\(\mu_k\)): 70% of the coefficient of static friction (\(\mu_s\))**Question:**What is the coefficient of static friction (\(\mu_s\)) between the crate and the warehouse floor?### Explanation and Solution:1. **Kinetic Friction and Stopping Distance:** When the crate falls and slides to a stop, kinetic friction is the force that brings it to rest. The work done by this frictional force over the distance of 2.5 m is equal to the kinetic energy the crate had initially.2. **Equations Involved:** - Kinetic energy (\(KE\)): \[ KE = \frac{1}{2} m v_i^2 \] - Work done by friction (\(W\)): \[ W = F_k \cdot d \] - Force of kinetic friction (\(F_k\)): \[ F_k = \mu_k \cdot N \] where \(N\) is the normal force, \(N = m \cdot g\).3. **Steps to Find \(\mu_s\):** 1. Calculate the initial kinetic energy (\(KE\)). 2. Set up the work-energy equation: \( KE = F_k \cdot d \). 3. Rearrange to find \(F_k \). 4. Calculate \(\mu_k\). 5. Use the given relationship \(\mu_k = 0.7 \mu_s\) to solve for \(\mu_s\).**Detailed Solution:**1. **Calculate initial kinetic energy:** \[ KE = \frac{1}{2} \cdot 40 \, \text{kg} \cdot (3 \, \text{m/s})^2 \] \[ KE = \frac{1}{2} \cdot 40 \cdot

Name: ### Problem Statement:**Scenario:**A 40 kg crate falls off a forklift
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Description: ### Problem Statement:**Scenario:**A 40 kg crate falls off a forklift moving at 3 m/s and slides along the warehouse floor, coming to rest after covering a distance of 2.5 m.**Given Data:**- Mass of the crate (\(m\)): 40 kg- Initial velocity (\(v_i\

Given:mass of crate, m = 40 kgco-efficient of kinetic friction be μk co-efficient of static friction…

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(b) The coefficient of kinetic friction between a 40 kg crate and the ware- house floor is 70% of the corresponding coefficient of static friction. The crate falls off a forklift that is moving at 3 m/s and then slides along the warehouse floor for a distance of 2.5 m before coming to rest. What is the coefficient of static friction between the crate and the floor?

(b) The coefficient of kinetic friction between a 40 kg crate and the ware- house floor is 70% of the corresponding coefficient of static friction. The crate falls off a forklift that is moving at 3 m/s and then slides along the warehouse floor for a distance of 2.5 m before coming to rest. What is the coefficient of static friction between the crate and the floor?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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