B Support reactions will be found in the gerber beam whose loading condition is given in the figure. Ais the fixed joint, the G point is the intermediate joint, and the B and C supports are the sliding joint. Loads on the beam Pl = 24 kN, P2 = 2 kN, %3D q = 4 kN/m, beam dimensions a = 4 m, b = 2 m. Accordingly, Gy = ? Da) 10.5 OB) None. OC) 4 OD) 0 OTO) 6

B Support reactions will be found in the gerber beam whose loading condition is given in the figure. Ais the fixed joint, the G point is the intermediate joint, and the B and C supports are the sliding joint. Loads on the beam Pl = 24 kN, P2 = 2 kN, %3D q = 4 kN/m, beam dimensions a = 4 m, b = 2 m. Accordingly, Gy = ? Da) 10.5 OB) None. OC) 4 OD) 0 OTO) 6

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Please Show clear work and free body diagram if possible, thank you!
Include the ff. 1.)The original figure and requirement(s) 2.)Free body diagram with complete labels 3.) Formulas and its proper symbols 4.) Direction
İ need very quick help to solve these questions pls help
Refer to the beam shown below. Internal hinges are installed at points C and E. P = 47.25 kN P (KN) 20 kN/m A D E F +200 mt200 m-i -200 m-| 1 m|- 3.00 m- 2.00 m- - 2.00 m- 1 m a) Determine the support reactions. b) Calculate for the maximum positive and negative bending moment. c) Draw the shear and moment diagram (specify magnitudes at indicated points A, B, C, D, E, at maximum and minimum points, zero shear/s, zero moment/s etc.)
Please solve this question in 40 mins i will give you positive feedback. Donot miss any subpart clearly mention each subpart
Calculate the reaction of the beam supports in the loading condition shownin the figure. kG a) O Ay 610 kG, By = 512 kG b) O Ay= 685 kG, By 441KG w(b) = 500 %D )O Ay- 592 kG , By = 523 kG b-3 4m d) O Ay= 643 kG, By- 482 kG
3. The simply-supported beam shown below has the cross-sectional area shown in on the right. Draw shear and moment diagrams. Determine the max bending stress and max transverse shear in the beam. 6 m a) b) Tmax-bending= Tmax-transverse = 5kN/m 20 mm N 20 mm MPa MPa B 20 mm- C 250 mm 150 mm 150 mm D A
Question Four A beam of the cross section that is shown in Figure a was supported by two rigid supports that tilt by 45° from the horizontal ( see Figure b). The own weight (w) of the beam is 1.5 kN/m. allowable tensile stress (o), = 50 MPa. Calculate the maximum length (L) of the beam that can be supported. 20 cm ... 45 If the maximum %3D 40 cm 15 cm 10 cm (а) 450 (b)
Find the slope and vertical deflection at point A using the Method of Superposition. Use E= 31,000 ksi and I = 246 in4. 3 kip B 2 kip/ft 3 ft- 3 ft A
PROBLEM 1 A cantilever beam of length 1.5 is loaded by concentrated force P at free end and is circular cross section (radius = 100mm), having two symmetrically placed longitudinal holes of radii R/3 with centers at R/2 above and below the neutral axis. The material is titanium alloy, having an allowable working stress in bending is 600 MPa. A) Calculate the Value of "C" in inches B) Solve for I C) Find the value of radii for both of two symmetrical placed longitudinal holes? D) Mmax? E) Pmax?
None
2 A beam is loaded as shown in Fig. 2. Determine the support reactions and sketch the FBD, SFD and BMD for the beam. Neat sketches are required. 1750N 035m b) f1200N V O'40m 025m Frg. 2