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(b) s) Now add the two's complement of 27 to 109. The result should be the same as 100-18. Binary Нех 2's(27) Ox E7 10910 Ох 6D 2's(27) + 10910 Ox (c) Now divide the result of the addition from part 1(b) by 4 using a bit shift. Binary Нех (2's(27) + 10910)/4 Ox (d) ( ) Convert the result from part 1(c) to decimal.

(b) s) Now add the two's complement of 27 to 109. The result should be the same as 100-18. Binary Нех 2's(27) Ox E7 10910 Ох 6D 2's(27) + 10910 Ox (c) Now divide the result of the addition from part 1(b) by 4 using a bit shift. Binary Нех (2's(27) + 10910)/4 Ox (d) ( ) Convert the result from part 1(c) to decimal.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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(b) s) Now add the two's complement of 27 to 109. The result should be the same as 100-18. Binary Нех 2's(27) Ox E7 10910 Ох 6D 2's(27) + 10910o Ox (c) Now divide the result of the addition from part 1(b) by 4 using a bit shift. Binary Нех (2's(27) + 10910)/4 Ox (d) ( ) Convert the result from part 1(c) to decimal.
Transcribed Image Text:(b) s) Now add the two's complement of 27 to 109. The result should be the same as 100-18. Binary Нех 2's(27) Ox E7 10910 Ох 6D 2's(27) + 10910o Ox (c) Now divide the result of the addition from part 1(b) by 4 using a bit shift. Binary Нех (2's(27) + 10910)/4 Ox (d) ( ) Convert the result from part 1(c) to decimal.
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