b r The diagram below show the inner section of a circular conductor of inner part and outside radius b this transfer current. magnetic field at radial=? a) r< a b) ab

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b
r
The diagram below show the inner section of a circular conductor of inner part and outside radius b
this transfer current.
magnetic field at radial=?
a) r< a
b) a<r<b
c) r>b
Transcribed Image Text:b r The diagram below show the inner section of a circular conductor of inner part and outside radius b this transfer current. magnetic field at radial=? a) r< a b) a<r<b c) r>b
Expert Solution
Step 1

According to Ampere's Law,

B.dl = μ0Ienclosed

note-

  • considering the conductor carries a current I

a) for r<a

The total charged enclosed in the region r<a is zero,

Ienclosed = 0

using the ampere's law,

B.dl = μ0IenclosedB.dl = 0B = 0

so the magnetic field inside the region r<a is 0.

 

 

Step 2

b) for a<r<b

The current enclosed in a cylindrical shell of inner radius 'a' and outer radius 'r' is 

Ienclosed = Iπ(b2-a2)×πr2 - a2Ienclosed  = I(b2-a2)r2 - a2

From ampere's law,

B.dl = μ0IenclosedB.dl = μ0I(r2-a2)b2-a2B2πr = μ0I(r2-a2)b2-a2B = μ02πrI(r2-a2)b2-a2

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