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(b) Perform a Z-test and find the p-value. Here is some information to help you with your z-test. • The value of the test statistic is given by The p-value is two times the area under the curve to the left of the value of the test statistic. Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. G Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. o Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85.

(b) Perform a Z-test and find the p-value. Here is some information to help you with your z-test. • The value of the test statistic is given by The p-value is two times the area under the curve to the left of the value of the test statistic. Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. G Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. o Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85.

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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(b) Perform a z-test and find the p-value. Here is some information to help you with your z-test. • The value of the test statistic is given by The p-value is two times the area under the curve to the left of the value of the test statistic. Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. x-μ G Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85.
Transcribed Image Text:(b) Perform a z-test and find the p-value. Here is some information to help you with your z-test. • The value of the test statistic is given by The p-value is two times the area under the curve to the left of the value of the test statistic. Step 2: Enter the test statistic. (Round to 3 decimal places.) Step 3: Shade the area represented by the p- value. x-μ G Step 4: Enter the p- value. (Round to 3 decimal places.) 0.3 0.2 0.1 (c) Based on your answer to part (b), choose what can be concluded, at the 0.05 level of significance, about the claim made by the management. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is less than (or equal to) the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is rejected. So, there is enough evidence to support the claim that the mean customer rating is not equal to 85. Since the p-value is greater than the level of significance, the null hypothesis is not rejected. So, there is not enough evidence to support the claim that the mean customer rating is not equal to 85.
Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, μ, is not equal to 85. In a sample of 43 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the claim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis and the alternative hypothesis H₁. Ho HO (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by o One-tailed O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) x-μ Step 3: Shade the area represented by the p- value. 0.3 • The p-value is two times the area under the curve to the left of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. 0.2 H 0.1 O<0 000>O 020 0-0 OD X $
Transcribed Image Text:Over the years, the mean customer satisfaction rating at a local restaurant has been 85. The restaurant was recently remodeled, and now the management claims the mean customer rating, μ, is not equal to 85. In a sample of 43 customers chosen at random, the mean customer rating is 84.1. Assume that the population standard deviation of customer ratings is 5.2. Is there enough evidence to support the claim that the mean customer rating is different from 85? Perform a hypothesis test, using the 0.05 level of significance. (a) State the null hypothesis and the alternative hypothesis H₁. Ho HO (b) Perform a Z-test and find the p-value. Here is some information to help you with your Z-test. • The value of the test statistic is given by o One-tailed O Two-tailed Step 2: Enter the test statistic. (Round to 3 decimal places.) x-μ Step 3: Shade the area represented by the p- value. 0.3 • The p-value is two times the area under the curve to the left of the value of the test statistic. Standard Normal Distribution Step 1: Select one-tailed or two-tailed. 0.2 H 0.1 O<0 000>O 020 0-0 OD X $
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