(b) Noting that f'(x) is also another function of æ, what is the linear approximation of f'(x) in terms of g(x), its derivatives, x, and ro? Hint: Consider how f(x), g(x), and their (possibly higher-than-first- order) derivatives at ro are related.

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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Calculus Problem: Linear Approximation and Derivatives**

**Problem 1:** Consider some arbitrary function \( f(x) \), whose value and whose derivative values of every order are already known at some point \( x_0 \). We can approximate the function value \( f(x) \) with \( f(x_0) + f'(x_0)(x - x_0) \) for points \( x \) that are very close to \( x_0 \).

1. **(a) Justify this "linear" approximation using the graphical interpretation of the derivative. Because this is an approximation, there will be a discrepancy between the actual \( f(x) \) and our approximation - call this \( g(x) \), and write down an expression for \( f(x) \) including \( g(x) \). (The approximation is called linear due to how the \( (x - x_0) \) term is first-order.) You may use the graph of \( f(x) = e^x \), with your own choice of \( x_0 \), as an illustrative example.**

**Explanation**: When implementing the linear approximation \( f(x) \approx f(x_0) + f'(x_0)(x - x_0) \), this suggests that for values of \( x \) close to \( x_0 \), the function \( f(x) \) can be approximated by the tangent line at \( x = x_0 \). The approximation discrepancy \( g(x) \) accounts for the non-linearity of \( f(x) \). 

2. **(b) Noting that \( f'(x) \) is also another function of \( x \), what is the linear approximation of \( f'(x) \) in terms of \( g(x) \), its derivatives, \( x \), and \( x_0 \)? Hint: Consider how \( f(x) \), \( g(x) \), and their (possibly higher-than-first-order) derivatives at \( x_0 \) are related.**

**Explanation**: To approximate \( f'(x) \), similar principles apply as in the approximation of \( f(x) \). Utilizing \( g(x) \) and the higher-order derivatives, we can estimate the changes in the slope of \( f(x) \).

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**Graphical Context**: If using a function like \( f(x)
Transcribed Image Text:--- **Calculus Problem: Linear Approximation and Derivatives** **Problem 1:** Consider some arbitrary function \( f(x) \), whose value and whose derivative values of every order are already known at some point \( x_0 \). We can approximate the function value \( f(x) \) with \( f(x_0) + f'(x_0)(x - x_0) \) for points \( x \) that are very close to \( x_0 \). 1. **(a) Justify this "linear" approximation using the graphical interpretation of the derivative. Because this is an approximation, there will be a discrepancy between the actual \( f(x) \) and our approximation - call this \( g(x) \), and write down an expression for \( f(x) \) including \( g(x) \). (The approximation is called linear due to how the \( (x - x_0) \) term is first-order.) You may use the graph of \( f(x) = e^x \), with your own choice of \( x_0 \), as an illustrative example.** **Explanation**: When implementing the linear approximation \( f(x) \approx f(x_0) + f'(x_0)(x - x_0) \), this suggests that for values of \( x \) close to \( x_0 \), the function \( f(x) \) can be approximated by the tangent line at \( x = x_0 \). The approximation discrepancy \( g(x) \) accounts for the non-linearity of \( f(x) \). 2. **(b) Noting that \( f'(x) \) is also another function of \( x \), what is the linear approximation of \( f'(x) \) in terms of \( g(x) \), its derivatives, \( x \), and \( x_0 \)? Hint: Consider how \( f(x) \), \( g(x) \), and their (possibly higher-than-first-order) derivatives at \( x_0 \) are related.** **Explanation**: To approximate \( f'(x) \), similar principles apply as in the approximation of \( f(x) \). Utilizing \( g(x) \) and the higher-order derivatives, we can estimate the changes in the slope of \( f(x) \). --- **Graphical Context**: If using a function like \( f(x)
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