b) In this part you will show that for each positive integer n, F? – Fr+1 F-1 = (-1)*+!. Show that this eguality is true for n -

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Sequence and series - Part b

(b) In this part you will show that for each positive integer n,
FR-Fr+1 Fn-1 = (-1)까!.
i. Show that this equality is true for n = 1.
ii. Show that
F1 - Fn+2 F, = 2F, F,-1 + F1 – Fn+1 Fn.
iii. Show that
2F, F,-1 + F, - Fn+1 F, = F + Fn-1 F, – F? .
iv. Show that
F + F,-1 F, – F = (-1)(F? – F„-1 Fn+1).
v. Combine subparts i--iv to show that if F? – Fn+1 Fn=1 = (-1)*+1 for some positive integer n, then
F - Fn+2 F, = (-1)*+2.
By subpart i, the equality is true for n = 1. By subpart v, the equality is true for n = 2. Applying subpart v again, the equality is true for n = 3,
and so on . Therefore, for each positive integer n,
FR-Fr+1 Fn-1 = (-1)까!.
This is called a proof by induction.
Transcribed Image Text:(b) In this part you will show that for each positive integer n, FR-Fr+1 Fn-1 = (-1)까!. i. Show that this equality is true for n = 1. ii. Show that F1 - Fn+2 F, = 2F, F,-1 + F1 – Fn+1 Fn. iii. Show that 2F, F,-1 + F, - Fn+1 F, = F + Fn-1 F, – F? . iv. Show that F + F,-1 F, – F = (-1)(F? – F„-1 Fn+1). v. Combine subparts i--iv to show that if F? – Fn+1 Fn=1 = (-1)*+1 for some positive integer n, then F - Fn+2 F, = (-1)*+2. By subpart i, the equality is true for n = 1. By subpart v, the equality is true for n = 2. Applying subpart v again, the equality is true for n = 3, and so on . Therefore, for each positive integer n, FR-Fr+1 Fn-1 = (-1)까!. This is called a proof by induction.
The Fibonacci sequence is the sequence { F, }, defined by Fo = 0, F = 1, and
n In=0
F, = Fn-1 + F-2
for each n = 2, 3, 4, ...
Transcribed Image Text:The Fibonacci sequence is the sequence { F, }, defined by Fo = 0, F = 1, and n In=0 F, = Fn-1 + F-2 for each n = 2, 3, 4, ...
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