(b) In the (x, y)-plane, sketch the vector fields v = (y, 2y, 0) and w = (x−y, x+y, 0), clearly labelling which sketch is for which field.
(b) In the (x, y)-plane, sketch the vector fields v = (y, 2y, 0) and w = (x−y, x+y, 0), clearly labelling which sketch is for which field.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:(b) In the (x, y)-plane, sketch the vector fields v = (y, 2y, 0) and w = (x−y, x+y, 0),
clearly labelling which sketch is for which field.
(c) For the vector fields defined in part (b), evaluate separately each term in the iden-
tity given in part (a) and hence verify the identity in this case.
(d) The vector field F has the form F(r) g(r)a, where g(r) is an arbitrary
differentiable scalar field and a is a constant vector. Use index notation to express
curl F in terms of grad g. Hence, by applying Stokes's theorem to the field F,
show that
g dr
- 1/791
Vg x dS,
==
with S a smooth open orientable surface bounded by the simple closed curve C.
You may assume the scalar triple product rule b × c·d=b∙c×d if vectors b, c
and d are not operators.
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