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- iii) Consider a 2D square potential energy well with sides L (length) containing six electrons. The potential energy is infinite at the sides and zero inside. The h? single-particle energies are given by 8mL +n), where n and ny are integers. If a seventh electron is added to the system when it is in its ground state find the least energy the additional electron can have?6. Use Boltzmann distribution to solve this problem. A system consists of 3,000 particles that can only occupy two energy levels: a nondegen- erate ground state of 0.052 eV and a threefold degenerate excited state at 0.156 eV. If T = 900 K, (а) find the number of particles at each energy level. –0156 ev (b) what is the total energy of the system? 0,052 ev4. What is the maximum acceleration potential (V) must be applied to electrons to cause electron diffraction on (220) planes of Lithium at 0 = 5°? (aLi = 3.517A°, m. = 9.1093837015 × 10' kg, q. = 1.6 × 10-19 coulomb, h = 6.62 x 10 34 J.S).
- In the Franck-Hertz experiment, explain why the small potential difference between the grid and collector plate is useful. Redraw the data of Figure the way the data would appear without this small retarding potential.A certain X-ray machine generates X-rays from a beam of electrons accelerated from zero to 99.9999999 per cent the speed of light in a long linear accelerator of length 3.2 km. The electrons are generated in pulses of duration ∆t = 100 fs. The generated x-rays from the target are also short pulses (λ = 0.15 nm). Determine the energy of a single x-ray photon in the beam. a.) 8.27 eV b.) 8.27 J c.) 8.27 keV d.) none of these.Four different particles are trapped in one dimensional wells with infinite potential at the walls and zero potential inside. The masses of the particles and their energy level, n , are given by: 1. mass=m, n=1 2. mass=2m, n=2 3. mass =3m, n=3 4. mass=4m, n=2 All these wells have the same length L. Rank the kinetic energy of the particles in order of size, smallest to largest. Group of answer choices E3 <E1<E2<E4 E1 = E4 < E2 < E3 E4 <E3 <E2 = E1 E1 < E2 = E4 < E3 E1 < E2 = E3 <E4