(b) (i) State Newton’s third of motion. (ii) A Caribbean airplane on its way from the Piarco International Airport to the Grantley Adams International Airport flies horizontally in mid-flight. With the aid of a diagram, and using Newton’s third law of motion, explain how this happens.
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(b) (i) State Newton’s third of motion.
(ii) A Caribbean airplane on its way from the Piarco International Airport to the Grantley Adams International Airport flies horizontally in mid-flight.
With the aid of a diagram, and using
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- Suppose an astronaut landed on a planet where g = 19.6 m>s2. Compared to earth, would it be easier, harder, or just as easy for her to walk around? Would it be easier, harder, or just as easy for her to catch a ball that is moving horizontally at 12 m>s? (Assume that the astronaut’s spacesuit is a lightweight model that doesn’t impede her movements in any way.)In solar and lunar eclipses the Sun, Moon, and Earth line up in a straight line. During which eclipse will the Moon experience the greatest net force? Determine the magnitude and direction of the force. [Hint: Use the Law of Universal Gravitation!](a) Find the magnitude of the gravitational force (in N) between a planet with mass 7.75 x 1024 kg and its moon, with mass 2.20 x 1022 kg, if the average distance between their centers is 2.90 x 10° m. (b) What is the moon's acceleration (in m/s?) toward the planet? (Enter the magnitude.) m/s2 (c) What is the planet's acceleration (in m/s²) toward the moon? (Enter the magnitude.) m/s?
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- (a) Find the magnitude of the gravitational force (in N) between a planet with mass 8.25 x 104* kg and its moon, with mass 2.20 x 1042 kg, if the average distance between their centers is 2.90 x 108 m. (b) What is the moon's acceleration (in m/s) toward the planet? (Enter the magnitude.) m/s2 (c) What is the planet's acceleration (in m/s²) toward the moon? (Enter the magnitude.) m/s2 Need Help? Read It Watch ItNote that the angles start from zero and increase to 360°. By convention, angles are given relative to the positive x-axis. For this purpose, choose the positive x-axis as pointing toward 0°, and the negative x-axis as pointing towards 180°, the positive y-axis at 90° and the negative y-axis at 270°. (a) A: 200 g along +x axis B: 100 g 45° above -x axis II: (a) A: 150 g 60° along +y axis B: 200 g 45° above -x axis C: 100 g 30° below -x axis COMPONENT METHOD: (b) A: 100 g 30° above -x axis B: 150 g along -y axis (b) A: 150 g 30° below +x axis B: 200 g 60° above +x axis C: 150 g 60° above -x axis For both parts I and II, use the component method to find the resultants and their directions Using the component method (for two given vectors), we can write Ax + Bx = Rx; Ay + By = Ry For three given forces in Part II, this can be rewritten as Ax + Bx + Cx = Rx; Ay + By + Cy = R₂ The magnitude of R in each case, is found using Pythagoras theorem: R = √ (R₂²+R₂²) and the direction (the angle q…(a)find the magnitude of the gravitational force (in N) between a planet with mass 6.50x10^24 kg and its moon, with mass 2.65x10^22 kg, if the average distance between theircenters is 2.20x10^8 m. (b)what is the moons acceleration (in m/s2) toward the planet? (enter the magnitude) (c)What is the planet's acceleration (in m/s2) toward the moon? (Enter the magnitude.)
- In physics, it is established that the acceleration due to gravity, g (in meters/sec2 ), at a height h meters above sea level is given by g(h) = 3.99 * 1014/(6.374 * 106 + h) 2 where 6.374 * 106 is the radius of Earth in meters. (a) What is the acceleration due to gravity at sea level? (b) The Willis Tower in Chicago, Illinois, is 443 meters tall. What is the acceleration due to gravity at the top of the Willis Tower? (c) The peak of Mount Everest is 8848 meters above sea level. What is the acceleration due to gravity on the peak of Mount Everest? (d) Find the horizontal asymptote of g(h). (e) Solve g1h2 = 0. How do you interpret your answer?By Newton's universal law of gravitation the free-fall acceleration a of a body, such as the satellite shown in the figure, falling a great distance to the surface is not the constant g. Rather, the acceleration a is inversely proportional to the square of the distance from the center of the Earth, a = k/r2, where k is the constant of proportionality. Use the fact that at the surface of the Earth r = R and a = g to determine k. If the positive direction is upward, use Newton's second law and his universal law of gravitation to find a differential equation for the distance r. k = d?r dt2 satellite of mass m surface Earth of mass MWhich of the following statements is correct? [A] The acceleration due to gravity is same at the equator and the poles [B] The acceleration due to gravity is maximum at the poles [C] The acceleration due to gravity is least at the poles [D] None of the above