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(b) How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop? J

(b) How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop? J

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Question (b): How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop?** Explanation: This question involves calculating the work required to stop an automobile. The work done on an object is related to the change in its kinetic energy. The kinetic energy (KE) of an object is given by the equation: \[ KE = \frac{1}{2}mv^2 \] where \( m \) is the mass of the object (980 kg) and \( v \) is its velocity (72 km/h). To find the work done, you need to convert the velocity from kilometers per hour to meters per second, use the kinetic energy formula, and determine the change in kinetic energy (from its initial value to zero, since the automobile stops).
Transcribed Image Text:**Question (b): How much work would have to be done to bring a 980-kg automobile traveling at 72 km/h to a stop?** Explanation: This question involves calculating the work required to stop an automobile. The work done on an object is related to the change in its kinetic energy. The kinetic energy (KE) of an object is given by the equation: \[ KE = \frac{1}{2}mv^2 \] where \( m \) is the mass of the object (980 kg) and \( v \) is its velocity (72 km/h). To find the work done, you need to convert the velocity from kilometers per hour to meters per second, use the kinetic energy formula, and determine the change in kinetic energy (from its initial value to zero, since the automobile stops).
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