b) Given an RL circuit with the equation UTM UTM IP L +RI = 900, dt where L is the inductance, R is the resistance and 900 is the voltage UTM UTM source. i. Show that the solution of the above equation is UTM UTM UT UTM UTM UTM UTMAUTM 900 I(t) = UTM UT + Ce-4. R ii. The series are connected with inductance 350 henry, and the resistance is 18 ohms. Find 1(t) if the initial current I(0) = 0. Calculate the current I(t) at time t 1 minute. UTM UTM UTM TMUT UT

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
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b) Given an RL circuit with the equation
UTM
d+RUTMUT
+ RI = 900,
UTM
IP
where L is the inductance, R is the resistance and 900 is the voltage
source.
UT
i. Show that the solution of the above equation is
UTM UT
UTM
UTM
900
I(t) =
UTM UT
UTMUTM AUT
+Ce-
ii. The series are connected with inductance 350 henry, and the resistance
is 18 ohms. Find I(t) if the initial current I(0) = 0. Calculate the
current I(t) at time t= 1 minute.
UTM
UTM
UTMUTM UTM
UTM UTM UT
UTMUT
Transcribed Image Text:b) Given an RL circuit with the equation UTM d+RUTMUT + RI = 900, UTM IP where L is the inductance, R is the resistance and 900 is the voltage source. UT i. Show that the solution of the above equation is UTM UT UTM UTM 900 I(t) = UTM UT UTMUTM AUT +Ce- ii. The series are connected with inductance 350 henry, and the resistance is 18 ohms. Find I(t) if the initial current I(0) = 0. Calculate the current I(t) at time t= 1 minute. UTM UTM UTMUTM UTM UTM UTM UT UTMUT
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