b₁ Five pairs of data values are shown below. Complete the table. (sum) Σ Linear Regression Σ x² /=1 Σ ν - - Σ - Σ ν n 1-1 i=1 1 n f=1 b₁ = Ỹ - b₁ X = — - Σ n =1 3 y₁ - 4 bex n 1-1 5 6 ž 3 (a) Find the mean and standard deviation of y. y = Mean of y = (1/N) Σ yn 0.5 5 7 8 Mean of y= Standard dev. of y = (b) Find the coefficients of the "best" line fit to the data Y = bí X + bo x² x*y 9 b₁ = 16 25 35 36 48 20 Standard dev. of y = [(1/(N-1)) Σ (yn-y)² ] 1/2 bo=
b₁ Five pairs of data values are shown below. Complete the table. (sum) Σ Linear Regression Σ x² /=1 Σ ν - - Σ - Σ ν n 1-1 i=1 1 n f=1 b₁ = Ỹ - b₁ X = — - Σ n =1 3 y₁ - 4 bex n 1-1 5 6 ž 3 (a) Find the mean and standard deviation of y. y = Mean of y = (1/N) Σ yn 0.5 5 7 8 Mean of y= Standard dev. of y = (b) Find the coefficients of the "best" line fit to the data Y = bí X + bo x² x*y 9 b₁ = 16 25 35 36 48 20 Standard dev. of y = [(1/(N-1)) Σ (yn-y)² ] 1/2 bo=
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![1.
b₁
Five pairs of data values are shown below. Complete the table.
x² x*y
(sum) Σ
Mean of y=
Linear Regression
=
y = Mean of y (1/N) Σ yn
1
-².
n
1-1
É ×² - - -( É
1
n
/=1
X
1
3
x₁ >, y₁
i=1
4
x₁
5
6
2
(a) Find the mean and standard deviation of y.
3
bo
= Y - b₁ X = = - Σ v₁ - bx,
n 1=1
n =1
5
7
8
Standard dev. of y =
(b) Find the coefficients of the "best" line fit to the data
Y = b1 X + bo
16
9
20
25
35
36 48
b₁ =
Standard dev. of y = [(1/(N-1)) Σ (yn-y) ² ] 1/2
bo=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8ce6f6e3-a53e-4898-b247-4366f6e6c1b7%2F731e1c27-3f1a-42ce-bec4-271d3d240864%2Fit0x0jc_processed.jpeg&w=3840&q=75)
Transcribed Image Text:1.
b₁
Five pairs of data values are shown below. Complete the table.
x² x*y
(sum) Σ
Mean of y=
Linear Regression
=
y = Mean of y (1/N) Σ yn
1
-².
n
1-1
É ×² - - -( É
1
n
/=1
X
1
3
x₁ >, y₁
i=1
4
x₁
5
6
2
(a) Find the mean and standard deviation of y.
3
bo
= Y - b₁ X = = - Σ v₁ - bx,
n 1=1
n =1
5
7
8
Standard dev. of y =
(b) Find the coefficients of the "best" line fit to the data
Y = b1 X + bo
16
9
20
25
35
36 48
b₁ =
Standard dev. of y = [(1/(N-1)) Σ (yn-y) ² ] 1/2
bo=
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