Please help me work through the attached question? (b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to.10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediatecalculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.)z =0.49p-value =0.623Reject HO at a =0.1but not at a =0.1, 0.05, 0.01 and 0.001noevidence that p1 and p2 differ.(c) Calculate a 95 percent confidence interval for the difference between the proportions of homeowners and renters who would buythe security system. On the basis of this interval, can we be 95 percent confident that these proportions differ? (Round your answersto confidence interval to 4 decimal places. Negative amounts should be indicated by a minus sign. )Confidence interval =(0.0851)0.1421 ]):No In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposal inwhich a telephone company wants to determine whether the appeal of a new security system varies between homeowners andrenters. Independent samples of 140 homeowners and 60 renters are randomly selected. Each respondent views a TV pilot in which atest ad for the new security system is embedded twice. Afterward, each respondent is interviewed to find out whether he or she wouldpurchase the security system.Results show that 25 out of the 140 homeowners definitely would buy the security system, while 9 out of the 60 renters definitelywould buy the system.(a) Letting p be the proportion of homeowners who would buy the security system, and letting p2 be the proportion of renters whowould buy the security system, set up the null and alternative hypotheses needed to determine whether the proportion ofhomeowners who would buy the security system differs from the proportion of renters who would buy the security system.HO: p1 – p2versus Ha: p1 – p2does not equal to 0(b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediatecalculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.)0.49p- value =0.623

Name: Please help me work through the attached question? (b) Find the test s
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Description: Please help me work through the attached question? (b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to.10, .05, .01, and .001. How much evidence is there that the

Given that 25 out of the 140 house owners definitely would buy the security system, while 9 out of…

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(b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to .10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediate calculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.) 0.49 p- value = 0.623 Reject HO at a = 0.1 but not at a = 0.1, 0.05, 0.01 and 0.001 no evidence that p1 and p2 differ. (c) Calculate a 95 percent confidence interval for the difference between the proportions of homeowners and renters who would buy the security system. On the basis of this interval, can we be 95 percent confident that these proportions differ? (Round your answers to confidence interval to 4 decimal places. Negative amounts should be indicated by a minus sign. ) (0.0851) 0.1421 ]: Confidence interval = No

(b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to .10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediate calculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.) 0.49 p- value = 0.623 Reject HO at a = 0.1 but not at a = 0.1, 0.05, 0.01 and 0.001 no evidence that p1 and p2 differ. (c) Calculate a 95 percent confidence interval for the difference between the proportions of homeowners and renters who would buy the security system. On the basis of this interval, can we be 95 percent confident that these proportions differ? (Round your answers to confidence interval to 4 decimal places. Negative amounts should be indicated by a minus sign. ) (0.0851) 0.1421 ]: Confidence interval = No

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Please help me work through the attached question?

(b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to
.10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediate
calculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.)
z =
0.49
p-value =
0.623
Reject HO at a =
0.1
but not at a =
0.1, 0.05, 0.01 and 0.001
no
evidence that p1 and p2 differ.
(c) Calculate a 95 percent confidence interval for the difference between the proportions of homeowners and renters who would buy
the security system. On the basis of this interval, can we be 95 percent confident that these proportions differ? (Round your answers
to confidence interval to 4 decimal places. Negative amounts should be indicated by a minus sign. )
Confidence interval =
(0.0851)
0.1421 ]):
No

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposal in
which a telephone company wants to determine whether the appeal of a new security system varies between homeowners and
renters. Independent samples of 140 homeowners and 60 renters are randomly selected. Each respondent views a TV pilot in which a
test ad for the new security system is embedded twice. Afterward, each respondent is interviewed to find out whether he or she would
purchase the security system.
Results show that 25 out of the 140 homeowners definitely would buy the security system, while 9 out of the 60 renters definitely
would buy the system.
(a) Letting p be the proportion of homeowners who would buy the security system, and letting p2 be the proportion of renters who
would buy the security system, set up the null and alternative hypotheses needed to determine whether the proportion of
homeowners who would buy the security system differs from the proportion of renters who would buy the security system.
HO: p1 – p2
versus Ha: p1 – p2
does not equal to 0
(b) Find the test statistic z and the p-value for testing the hypotheses of part a. Use the p-value to test the hypotheses with a equal to
10, .05, .01, and .001. How much evidence is there that the proportions of homeowners and renters differ? (Round the intermediate
calculations to 3 decimal places. Round your z value to 2 decimal and p-value to 3 decimal places.)
0.49
p- value =
0.623

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