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(b) Consider the following magnetic circuit where the circular core area is formed by Cast Steel. Find out the Flux to Reluctance ratio, 0/R (in Wb²/At). Given, A (throughout) = 10 m2; Relative permittivity of Cast Steel, µ, = 10Y + 2Z + 2500; Outer Radius of the core, r, = (3Y + 2Z + 5) mm; Inner Radius of the core, r; = (Y + Z + 2) mm; N = 20Y + 10Z + 230 I = 4A N2 = 5 (Y+ 6Z) + 75 I = 6A

(b) Consider the following magnetic circuit where the circular core area is formed by Cast Steel. Find out the Flux to Reluctance ratio, 0/R (in Wb²/At). Given, A (throughout) = 10 m2; Relative permittivity of Cast Steel, µ, = 10Y + 2Z + 2500; Outer Radius of the core, r, = (3Y + 2Z + 5) mm; Inner Radius of the core, r; = (Y + Z + 2) mm; N = 20Y + 10Z + 230 I = 4A N2 = 5 (Y+ 6Z) + 75 I = 6A

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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X=1 Y=3 Z=3
(b) Consider the following magnetic circuit where the circular core area is formed by Cast Steel. Find out the Flux to Reluctance ratio, D/R (in Wb²/At). Given, A (throughout) = 10 m²; Relative permittivity of Cast Steel, µ,= 10Y + 2Z + 2500; Outer Radius of the core, r, = (3Y + 2Z + 5) mm; Inner Radius of the core, r; = (Y + Z + 2) mm; N = 20Y + 10Z + 230 I = 4A N2 = 5 (Y+ 6Z) + 75 I = 6A 地
Transcribed Image Text:(b) Consider the following magnetic circuit where the circular core area is formed by Cast Steel. Find out the Flux to Reluctance ratio, D/R (in Wb²/At). Given, A (throughout) = 10 m²; Relative permittivity of Cast Steel, µ,= 10Y + 2Z + 2500; Outer Radius of the core, r, = (3Y + 2Z + 5) mm; Inner Radius of the core, r; = (Y + Z + 2) mm; N = 20Y + 10Z + 230 I = 4A N2 = 5 (Y+ 6Z) + 75 I = 6A 地
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