b) Calculate the centripetal acceleration of a car moving with a tangential velocity of 10.0 mls around a circle of radius 8.0 meters.

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Chapter6: Uniform Circular Motion And Gravitation
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**Question:** 

b) Calculate the centripetal acceleration of a car moving with a tangential velocity of 10.0 m/s around a circle of radius 8.0 meters.

**Explanation:**

To calculate the centripetal acceleration (\(a_c\)), we use the formula:

\[ a_c = \frac{v^2}{r} \]

where
- \( v \) is the tangential velocity
- \( r \) is the radius of the circle

Given:
- Tangential velocity, \( v = 10.0 \, \text{m/s} \)
- Radius, \( r = 8.0 \, \text{meters} \)

Now, substituting the given values into the formula:

\[ a_c = \frac{(10.0 \, \text{m/s})^2}{8.0 \, \text{meters}} \]
\[ a_c = \frac{100.0 \, \text{m}^2/\text{s}^2}{8.0 \, \text{meters}} \]
\[ a_c = 12.5 \, \text{m/s}^2 \]

Therefore, the centripetal acceleration of the car is \( 12.5 \, \text{m/s}^2 \).
Transcribed Image Text:**Question:** b) Calculate the centripetal acceleration of a car moving with a tangential velocity of 10.0 m/s around a circle of radius 8.0 meters. **Explanation:** To calculate the centripetal acceleration (\(a_c\)), we use the formula: \[ a_c = \frac{v^2}{r} \] where - \( v \) is the tangential velocity - \( r \) is the radius of the circle Given: - Tangential velocity, \( v = 10.0 \, \text{m/s} \) - Radius, \( r = 8.0 \, \text{meters} \) Now, substituting the given values into the formula: \[ a_c = \frac{(10.0 \, \text{m/s})^2}{8.0 \, \text{meters}} \] \[ a_c = \frac{100.0 \, \text{m}^2/\text{s}^2}{8.0 \, \text{meters}} \] \[ a_c = 12.5 \, \text{m/s}^2 \] Therefore, the centripetal acceleration of the car is \( 12.5 \, \text{m/s}^2 \).
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