(b) (c) -2a 2a T - a + 2b + 3c = 2b + b 2r + 4s 3r + 6s +2t 3t 5t С = с 11 = = 0 1 0 1 1 -3 ANS: Solution is: a = -5,b=-,c=-5 ANS: Solution is: {r= -17,8 = 11,t = 3}
(b) (c) -2a 2a T - a + 2b + 3c = 2b + b 2r + 4s 3r + 6s +2t 3t 5t С = с 11 = = 0 1 0 1 1 -3 ANS: Solution is: a = -5,b=-,c=-5 ANS: Solution is: {r= -17,8 = 11,t = 3}
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question

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Example 1.4.5
Compute the determinant of: A=
D
твсо
1
20
4
-2
1
4 3 0 1
2 3 -1
2-2 5
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a +
r +s
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2b + 3c = = 1
2b +
1
-3
4s
6s
C =
b - c
-
=
+ 2t = 0
1
3t =
5t
= 0
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ANS: Solution is: a = -5,b=-11, c= -5
ANS: Solution is: {r = −17, s = 11,t = 3}
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