B B 2) A loop like the one in #1 has a magnetic moment u= 0.085 Am² pointed into the page. If it is placed in a magnetic field B = 43 mT pointed at an angle of 35° out of the page from a line towards the top of the page (if the top of the page is North, the angle is 35° up from due North), what is the torque on the loop, t= µ x B?
B B 2) A loop like the one in #1 has a magnetic moment u= 0.085 Am² pointed into the page. If it is placed in a magnetic field B = 43 mT pointed at an angle of 35° out of the page from a line towards the top of the page (if the top of the page is North, the angle is 35° up from due North), what is the torque on the loop, t= µ x B?
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Magnetic Moment and Torque**
In this diagram, there is a circle labeled "B" at the center, surrounded by two more "B" labels on either side. This represents the presence of a magnetic field.
**Problem Statement:**
A loop, similar to the one mentioned in an earlier problem (#1), has a magnetic moment \( \mu = 0.085 \, \text{Am}^2 \) directed into the page. The loop is placed in a magnetic field \( B = 43 \, \text{mT} \), which is oriented at an angle of 35° out of the page, originating from a line directed towards the top of the page. If the top of the page is considered North, the angle is 35° upward from due North. The problem asks to find the torque on the loop, expressed as \( \tau = \mu \times B \).
**Key Concept:**
The torque (\( \tau \)) on a loop in a magnetic field is given by the cross product of the magnetic moment (\( \mu \)) and the magnetic field (\( B \)). The magnitude of the torque can be calculated using the formula:
\[ \tau = \mu B \sin(\theta) \]
where \( \theta \) is the angle between the magnetic moment and the magnetic field vector. In this case, \( \theta = 35^\circ \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65e8876c-9cfb-4d00-b5f3-6286bfdc9996%2F103e0413-6f6d-4748-9082-3c7f4e8ee8b9%2Fq8jn5q_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Magnetic Moment and Torque**
In this diagram, there is a circle labeled "B" at the center, surrounded by two more "B" labels on either side. This represents the presence of a magnetic field.
**Problem Statement:**
A loop, similar to the one mentioned in an earlier problem (#1), has a magnetic moment \( \mu = 0.085 \, \text{Am}^2 \) directed into the page. The loop is placed in a magnetic field \( B = 43 \, \text{mT} \), which is oriented at an angle of 35° out of the page, originating from a line directed towards the top of the page. If the top of the page is considered North, the angle is 35° upward from due North. The problem asks to find the torque on the loop, expressed as \( \tau = \mu \times B \).
**Key Concept:**
The torque (\( \tau \)) on a loop in a magnetic field is given by the cross product of the magnetic moment (\( \mu \)) and the magnetic field (\( B \)). The magnitude of the torque can be calculated using the formula:
\[ \tau = \mu B \sin(\theta) \]
where \( \theta \) is the angle between the magnetic moment and the magnetic field vector. In this case, \( \theta = 35^\circ \).
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