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(b) At T = 31.0°C, the resistance is given by R = Ro[1 + a(T-To)], where a is the temperature coefficient of resistivity. The current in the copper wire becomes AV Ro[1 + acu(T-To)] I = = AV R = 2.39 M)1 + (3.9 × 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%. °C 7.5 A.

(b) At T = 31.0°C, the resistance is given by R = Ro[1 + a(T-To)], where a is the temperature coefficient of resistivity. The current in the copper wire becomes AV Ro[1 + acu(T-To)] I = = AV R = 2.39 M)1 + (3.9 × 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%. °C 7.5 A.

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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(a) A 34.6-m length of copper wire at 20.0°C has a radius of 0.28 mm. If a potential difference of 7.50 V is applied across the length of the wire, determine the current in the wire. (b) If the wire is heated to 31.0°C while the 7.50-V potential difference is maintained, what is the resulting current in the wire? Step 1 (a) From the table below, the resistivity of copper at 20.0°C is Pcu coefficient of resistivity Cu have R = pL/A. Therefore, the resistance Ro of the copper wire at To = Ro = Pcu A = PCu² πr² -8 1.7 x 10 m with temperature 3.9 x 10-3 (°C)-¹. From the general relation between resistance and resistivity, we 20.0°C is given by the following. (1.7 x 1.7 x 10-8 m JU 0.28 m)( 34.6 34.6 m 0.28 x 10-3 m 2 = 2.38 2.39| Ω.
Transcribed Image Text:(a) A 34.6-m length of copper wire at 20.0°C has a radius of 0.28 mm. If a potential difference of 7.50 V is applied across the length of the wire, determine the current in the wire. (b) If the wire is heated to 31.0°C while the 7.50-V potential difference is maintained, what is the resulting current in the wire? Step 1 (a) From the table below, the resistivity of copper at 20.0°C is Pcu coefficient of resistivity Cu have R = pL/A. Therefore, the resistance Ro of the copper wire at To = Ro = Pcu A = PCu² πr² -8 1.7 x 10 m with temperature 3.9 x 10-3 (°C)-¹. From the general relation between resistance and resistivity, we 20.0°C is given by the following. (1.7 x 1.7 x 10-8 m JU 0.28 m)( 34.6 34.6 m 0.28 x 10-3 m 2 = 2.38 2.39| Ω.
Step 2 When a 7.50-V potential difference is applied across the length of this wire at 20.0°C, the resulting current Io is Io I = = AV Ro II AV R 7.50 Step 3 = (b) At T = 31.0°C, the res tance is given by R resistivity. The current in the copper wire becomes 2.39 2.39 7.5 V 2.39| Ω AV Ro[1 + acu(T - To)] A. 3.13 7.5 3.14 A. Ro[1 + a(TTO)], where a is the temperature coefficient of v) Ω 1 + (3.9 x 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%.°
Transcribed Image Text:Step 2 When a 7.50-V potential difference is applied across the length of this wire at 20.0°C, the resulting current Io is Io I = = AV Ro II AV R 7.50 Step 3 = (b) At T = 31.0°C, the res tance is given by R resistivity. The current in the copper wire becomes 2.39 2.39 7.5 V 2.39| Ω AV Ro[1 + acu(T - To)] A. 3.13 7.5 3.14 A. Ro[1 + a(TTO)], where a is the temperature coefficient of v) Ω 1 + (3.9 x 10-³ (°C)-¹)( 31.0 Your response differs from the correct answer by more than 100%.°
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