B and F (k²-k²²) (1-e²¹k'a) (k+k')² – (k − k')² e²¹k'a Prove the equation 4k²k²² (k²-K²) sin k'a (k²-K²) sin k'a 4K²K2 R= 4kk' e¹(k-k)a (k + k')² − (k − k'′)² e²ik'a - <=1+ 4E(E-V) Vsin k'a Vsin² k'a 4E(E-V)
B and F (k²-k²²) (1-e²¹k'a) (k+k')² – (k − k')² e²¹k'a Prove the equation 4k²k²² (k²-K²) sin k'a (k²-K²) sin k'a 4K²K2 R= 4kk' e¹(k-k)a (k + k')² − (k − k'′)² e²ik'a - <=1+ 4E(E-V) Vsin k'a Vsin² k'a 4E(E-V)
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Question
Transcribed Image Text:(k² – K²²) (1 – e2i** )
(k + k)² – (k – k)²e?*'a
В
2ik'a
A
4kk' e'(x'-k)a
(k + k')² – (k – k')² e2i*a
F
A
Prove the equation
|B|²
4k²k²²
4E(E – V,)
vỷ sin² k'a
vị sin² k'a
4E(E – V)
R=
)* sin² k'a
(k² – K²)² sin? k'a
4kK?
and
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