b) An arrow is shot straight upward from the ground with an initial velocity of 10 ms. The air resistance is equal to ku g, where v is the velocity of the arrow, k is a constant and g is the gravitational constant. The differential equation is given by dv TM dr -kv – 9. where r is the displacement of the arrow at time t which is taken as positive in the upward direction. Given that g 9.8 ms 2 and k = 0.05, i. Find the expression of the motion in terms of v and r. ii. Find the maximum height attained by the arrow. UTM UTM

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
Q1b
b) An arrow is shot straight upward from the ground with an initial
velocity of 10 ms-1. The air resistance is equal to ku g, where v is the
velocity of the arrow, k is a constant and g is the gravitational constant.
The differential equation is given by
UTMU
dv
UTM UTM
-kv – 9.
dr.
where z is the displacement of the arrow at time t which is taken as
TMUTM
%3!
positive in the upward direction. Given that g = 9.8 ms-² and
k = 0.05,
OUTM
TM
i. Find the expression of the motion in terms of v and r.
ii. Find the maximum height attained by the arrow.
SUTM&UTM
UTM
UTM UTM
UTMUTM
UTM
Transcribed Image Text:b) An arrow is shot straight upward from the ground with an initial velocity of 10 ms-1. The air resistance is equal to ku g, where v is the velocity of the arrow, k is a constant and g is the gravitational constant. The differential equation is given by UTMU dv UTM UTM -kv – 9. dr. where z is the displacement of the arrow at time t which is taken as TMUTM %3! positive in the upward direction. Given that g = 9.8 ms-² and k = 0.05, OUTM TM i. Find the expression of the motion in terms of v and r. ii. Find the maximum height attained by the arrow. SUTM&UTM UTM UTM UTM UTMUTM UTM
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