b) After the switch is flipped to the position B, the battery is no longer connected to the contour and the charge redistributes between the ca- pacitors as shown in Fig.2. Notice that I used the fact that the segment between the capacitors C₂ and C3 has to be neutral (therefore, they have the same charge), but the segments connecting C₁ to C₂ and C₁ to C3 are not neutral. What can you say about the sum of charges Q₁ and Q2? + 100V S -Q₁ Q₂ =Q₂ Q2 Q₂ FIG. 2: The scheme for Problem 1b

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Hi, I know there are multiple parts to this but I only need help is with part B can you help me with Part B. Thank you

### Problem 1:

Initially, the switch in Fig. 1 is in its position A and capacitors \( C_2 \) and \( C_3 \) are uncharged. Then the switch is flipped to position B. Afterward, what are the charge on and the potential difference across each capacitor?

**Partial answer:** \( \Delta V_1 = 55 \, \text{V}, \, \Delta V_2 = 33.5 \, \text{V} \).

#### a) 
While the capacitor is in position A, as shown in Fig. 1, compute the charge \( Q \) accumulated on the plates of the capacitor \( C_1 \).

**Figures:**
- **Fig. 1:** A circuit with a switch connecting a 100V battery to capacitors \( C_1 = 15 \, \mu \text{F} \), \( C_2 = 20 \, \mu \text{F} \), and \( C_3 = 30 \, \mu \text{F} \).

#### b) 
After the switch is flipped to position B, the battery is no longer connected to the contour and the charge redistributes between the capacitors as shown in Fig. 2. Notice that the segment between the capacitors \( C_2 \) and \( C_3 \) must be neutral (they have the same charge), but the segments connecting \( C_1 \) to \( C_2 \) and \( C_1 \) to \( C_3 \) are not neutral. What can you say about the sum of charges \( Q_1 \) and \( Q_2 \)?

**Figures:**
- **Fig. 2:** The circuit showing the distribution of charges \( Q_1 \) and \( Q_2 \) after the switch is flipped.

#### c) 
Use Kirchhoff’s loop law to get another relation between charges \( Q_1 \) and \( Q_2 \). Starting from point B in Fig. 2, move counterclockwise along the loop and register the potential differences that you encounter when crossing the capacitors (pay attention to the signs - when moving from a positively charged to a negatively charged plate, the potential decreases). The sum of all potential differences must be zero.

#### d) 
Your answers to parts b) and c) give you a system of two
Transcribed Image Text:### Problem 1: Initially, the switch in Fig. 1 is in its position A and capacitors \( C_2 \) and \( C_3 \) are uncharged. Then the switch is flipped to position B. Afterward, what are the charge on and the potential difference across each capacitor? **Partial answer:** \( \Delta V_1 = 55 \, \text{V}, \, \Delta V_2 = 33.5 \, \text{V} \). #### a) While the capacitor is in position A, as shown in Fig. 1, compute the charge \( Q \) accumulated on the plates of the capacitor \( C_1 \). **Figures:** - **Fig. 1:** A circuit with a switch connecting a 100V battery to capacitors \( C_1 = 15 \, \mu \text{F} \), \( C_2 = 20 \, \mu \text{F} \), and \( C_3 = 30 \, \mu \text{F} \). #### b) After the switch is flipped to position B, the battery is no longer connected to the contour and the charge redistributes between the capacitors as shown in Fig. 2. Notice that the segment between the capacitors \( C_2 \) and \( C_3 \) must be neutral (they have the same charge), but the segments connecting \( C_1 \) to \( C_2 \) and \( C_1 \) to \( C_3 \) are not neutral. What can you say about the sum of charges \( Q_1 \) and \( Q_2 \)? **Figures:** - **Fig. 2:** The circuit showing the distribution of charges \( Q_1 \) and \( Q_2 \) after the switch is flipped. #### c) Use Kirchhoff’s loop law to get another relation between charges \( Q_1 \) and \( Q_2 \). Starting from point B in Fig. 2, move counterclockwise along the loop and register the potential differences that you encounter when crossing the capacitors (pay attention to the signs - when moving from a positively charged to a negatively charged plate, the potential decreases). The sum of all potential differences must be zero. #### d) Your answers to parts b) and c) give you a system of two
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